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Natali [406]
3 years ago
11

If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?

Chemistry
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂  formed = 1/8 moles

Mass of CO₂  formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂  formed = 44 * 1/8

Mass of CO₂  formed = 5.5 grams

Hence, option B is correct

Kindly Mark Brainliest, Thanks!!!

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A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
Plz help u might find it easy
PIT_PIT [208]

The melting point of pure lead : 327 °C

<h3>Further explanation</h3>

Given

Amount of tin and melting point of solder

Required

The melting point

Solution

The composition of solder = tin and lead

So if it is 100% tin, 0% lead or 0% tin, 100% lead

From the table it is shown that when the position is 100% tin in the solder, the melting point of the solder is 232 °C, so it shows that the melting point of pure lead is obtained when% tin in solder = 0 (100% lead in solder), so that the melting point is obtained. : 327 °C

3 0
2 years ago
Someone help me quickkkkkkkkkkkkkk
Nana76 [90]
The picture isn’t loading smh
5 0
3 years ago
What is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 gram
oksano4ka [1.4K]

V₂O is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 grams of the oxide.

The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

Given

Vanadium weighs 20.38 g.

The oxide's mass is 23.58 g.

% Vanadium composition: (20.38 g/23.58 g) 100%

= 86.43%

Oxygen mass equals 23.58 g minus 20.38 g

= 3.2 g

100% of oxygen's composition is (3.2/g/23.58 g)

= 13.57%

Atomic mass and number are related by composition percentage.

Vanadium's atomic weight is 50.94 g/mol.

Atomic weight of V = 86.43 / 50.94

= 1.6967

Oxygen has an atomic mass of 16 g/mol.

O atom count is 13.57/16.

= 0.8481

Now on calculation the ratio of Vanadium to the oxygen is

1.6967/0.8481 = 2/1

Ratio of whole numbers is 2:1

Thus V₂O is the empirical formula .

Learn more about empirical formula here brainly.com/question/13058832

#SPJ4

6 0
11 months ago
How many hours are there in 34.5 years
4vir4ik [10]

Hi,

Answer: 30,2220 Hours

<u>My work:</u> There are 60 minutes in every hour and 8,760 hours in a year. To,easily achieve this problem you take 8,760 the hours in a year and multiply it with 34.5. (8,760 * 34.5) By doing this you get your answer of 302,220 Hours, or in minutes it would be 18,133,200 minutes.

I Hoped I Helped!

6 0
2 years ago
Read 2 more answers
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