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yuradex [85]
3 years ago
15

Ten boxes are packed tightly in a crate. From above, the packed crate looks like this: [asy] size(4cm); draw((0,10)--(12,10)--(1

2,0)--(0,0)--cycle,black+3); draw((0,7)--(12,7)); draw((0,4)--(12,4)); draw((4,10)--(4,4)); draw((8,10)--(8,4)); draw((3,4)--(3,0)); draw((6,4)--(6,0)); draw((9,4)--(9,0)); label("$\ell$",(6,10),N); draw((5.3,10+.9)--(0,10+.9),EndArrow(TeXHead)); draw((6.7,10+.9)--(12,10+.9),EndArrow(TeXHead)); label("$w$",(12,5),E); draw((12.9,5.7)--(12.9,10),EndArrow(TeXHead)); draw((12.9,4.3)--(12.9,0),EndArrow(TeXHead)); [/asy] The visible faces of the boxes are all congruent rectangles (that means the ten small rectangles in the diagram are the same shape and size). The top of the crate is $\ell$ inches long by $w$ inches wide, where $\ell\ge w$ (as shown above). What is the ratio $\ell:w$ in simplified form?
Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

can you show a picture or a more simplified version?

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Help and explain explain !!!!!!!!!!
tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

Therefore,

\implies \boxed{x=-1\text{ or }x=11}

3 0
3 years ago
Simplify Negative 15.6 divided by negative 4.
masha68 [24]
Simplify:

-15.6/-4

( \frac{-15.6}{-4} )

Divide to solve:

You get 3.9

3 0
3 years ago
If 2a+3<10 then which of these could be a value of a
solmaris [256]

Answer:

a < 3.5

Step-by-step explanation:

2a+3 <10

subtract 3 from each side

2a +3 -3 < 10-3

2a < 7

divide by 2

a < 7/2

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6 0
3 years ago
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Answer:

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3 0
3 years ago
Read 2 more answers
Find the average rate of change of f(x)=2x^2-7x from x=2 to x=5
m_a_m_a [10]

Answer:

7

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [2, 5 ]

f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15

f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus

average rate of change = \frac{15-(-6)}{5-2} = \frac{21}{3} = 7

3 0
3 years ago
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