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Ludmilka [50]
3 years ago
6

What is 37 sqaured on a number line

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
7 0

Answer:

6.08

Step-by-step explanation:

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Please help I need it!!!
ziro4ka [17]

Answer:

a

Step-by-step explanation:

it is being reflected of the other end

8 0
3 years ago
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Help me lawd!!!!!!!jkdmfkfm
Klio2033 [76]
This is equivalent to:

(2.2533/2.59)(10^8/10^4)

(0.87)(10^4) which is:

0.87X10^4  which is equal to:  

0.87X10000 which is equal to:

8.7X1000  and since 1000=10^3 we can say:

8.7X10^3
6 0
3 years ago
The pool holds 17,922 gallons of water, and is leaking at a rate of 4 gallons per day. If Mike does not replace the water that h
emmasim [6.3K]

Answer:

17442

Step-by-step explanation:

120x4= 480

17922-480=

3 0
3 years ago
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Which is the correct input-output table for the function f(x) = 3/x + 4
Ilia_Sergeevich [38]
Do u mean the inverse ?
f-^1(x)=3/x-4
7 0
4 years ago
How many of the numbers from 10 through 92 have the sum of their digits equal to a perfect​ square?
horrorfan [7]
All the numbers in this range can be written as 10d_1+d_0 with d_1\in\{1,2,\ldots,9\} and d_2\in\{0,1,\ldots,9\}. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)

so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.

For each number that occupies an entire diagonal in the table, it's easy to see that that number n shows up n times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.

So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.

7 0
3 years ago
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