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Korolek [52]
3 years ago
6

State the Pythagorean Theorem and how would you use it to find a missing side or missing hypotenuse of a right triangle.

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Answer:

Pythagorean Theorem: A² + B² = C²

You would use it to find a missing side or missing hypotenuse of a right triangle by pluggin in all of the known values of the triangle into the equation and then solving it.

Step-by-step explanation:

C² is the hypotenuse of the triangle (the longest side, and the side that is opposite the right angle).

A² and B² are the remaining two sides.

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Can someone answer this question please?
lakkis [162]

Answer:

Step-by-step explanation:

6 0
4 years ago
Whst is the remainder when f(x)=x^3+3x^2-10x-4 is diveded by x-3
Vesnalui [34]
The polynomial remainder theorem allows us to calculate the remainder when a polynomial is divided by a linear polynomial:
The remainder of f(x) divided by (x-k) equals f(k).

Thus
f(x)=x^3+3x^2-10x-4 divided by x-3
gives a remainder of
f(3)=27+3(9)-10(3)-4=27+27-30-4=20
Therefore the remainder required is 20.
6 0
3 years ago
write the equation of a line that is perpendicular to the given kine and that passes through the given point. -x+5y=14;(-5, -2)
Inga [223]
X + 5y = 14
5y = -x + 14
y = -1/5x + 14/5.....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will be 5. See how I flipped -1/5 making it -5/1...and then changed the sign, making it 5.

y = mx + b
slope(m) = 5
(-5,-2)....x = -5 and y = -2
now we sub and find b, the y int
-2 = 5(-5) + b
-2 = -25 + b
-2 + 25 = b
23 = b

so ur perpendicular equation is : y = 5x + 23 <==

7 0
3 years ago
Write an equation in standard form of the line shown.
11Alexandr11 [23.1K]

Answer: y= -2x + 4

Hope this helps.

7 0
3 years ago
Read 2 more answers
Please<br> <img src="https://tex.z-dn.net/?f=%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%28n%2B1%29%21%7D%7Bn%21-%28n%2B1%
Nana76 [90]
Hi there!
We are given the function - 
\lim_{n \to \infty} \frac{(n+1)!}{n!-(n+1)!}
and are told to find the limit of the function. 
The limit would be n approaches infinity, giving us an answer of -1. 
Here is how you solve this:
\frac{(n+1)!}{n!-(n+1)!}
Divide by (n + 1)! - 
\frac{1}{\frac{1}{n+1}-1 }
Now, we can refine the function - 
\lim_{n \to \infty}\frac{1}{\frac{1}{n+1}-1 }
Now, just simplify. This gives us - 
\lim_{n \to \infty} (1)
We can use the rule \lim_{x \to a}c=c to simplify the whole thing to get 1. Finally, we plug it back into our second derived equation to get 1/-1, which simplifies to -1. Therefore, the answer is -1. Hope this helped and have a great day!


3 0
3 years ago
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