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3 years ago

The line with x-intercept of 10 and y- intercept of -2.

Mathematics

1 answer:

Yuri [45]3 years ago

8 0

Answer:

y = $\frac{1}{5}$ x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ = x- intercept (10, 0) and (x₂, y₂ ) = y- intercept (0, - 2)

m = $\frac{-2-0}{0-10}$ = $\frac{-2}{-10}$ = $\frac{1}{5}$

The y- intercept c = - 2

y = $\frac{1}{5}$ x - 2 ← equation of line

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4 years ago

A baby giraffe was born at a wildlife preserve. The giraffe was 6 feet tall when it was born, and it grew 1.75 feet over the nex

HACTEHA [7]

The age of the giraffe when he is 15 feet tall be 1 year 1 month and 16 days.

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A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.

Giraffe height = 6 feet

Height grew in 7 months= 1.75 feet

Giraffe's height in 7 month = 7.75 feet

Giraffe's height, 1 feet= $\frac{7}{7.75}$ month

= 0.9032 months

Giraffe's height, 15 feet= 0.9032 x 15 month

= 13.548 month

= 13 months 16 days approx.

= 1 year 1 month 16 days

Hence, the age of giraffe will be 1 year, 1 month and 16 days

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2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

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