Answer:
The answer to this question is the option "B".
Explanation:
In this question, the answer is option B which is 1,000 because the kernel is a central part of an operating system. kernel manages the computer and the hardware operations. most especially memory and CPU time. It also sheared a memory variable is allocated to thread blocks. That's why the answer to this question is 1,000.
Answer:
The code will display the following on the screen:-
2
0
2
Explanation:
The output is like this because x{2} assigns the value 2 to the integer x.First the value of x is printed on the screen that is 2 and that newline is used to go to the next line.After that function is called doSomething with x passed as the argument. doSomething function assigns the value zero to the variable passed and prints it on the screen.So the next line is 0.Since x is passed by value so no changes will appear in the original argument.Hence the last line printed is 2.
Answer
Dispose of absorbents as hazardous waste in its own hazardous waste container
Explanation
Hazardous waste is a waste that has chemical composition and properties which makes it capable of causing illness, death or harm to humans and other life forms when released to the environment without proper management. The characteristics of such wastes include: toxic, ecotoxic, infectious substance, poisonous, explosive and flammability. Hazardous wastes can be destroyed by incineration, chemical process, and temporary on-site waste storage facilities such as waste piles and lagoons/ponds
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
