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dusya [7]
2 years ago
5

Help me solve this because I don't know how to solve it take your time

Mathematics
2 answers:
Stells [14]2 years ago
4 0
3 4 and 5 r ur answer :)
Yuki888 [10]2 years ago
3 0

Answers:

  1. Segment XA and segment MC
  2. Point N
  3. Points A, N and X
  4. Plane ANC
  5. No, they are not coplanar
  6. Ray NM and ray NX
  7. Ray NM and ray NC
  8. Three lines

==============================================

Explanation:

Problem 1

Technically there are no segments in this diagram because of the arrows that point in both directions for each line. However, you could make the argument that all you need to do is focus on two endpoints and that names a sub-segment of any given line. If this is what your teacher is going for, then two segments could be XA and MC

Something like "segment AC" isn't valid because there isn't a straight line connecting points A and C directly. So we can't pick any two points at random.

-----------------

Problem 2

Line CM and line RN intersect at point N

This point is on both lines simultaneously.

-----------------

Problem 3

Pick any three points that are on the same line. One such possible answer is Points A, N and X. They are all on the line XA.

Another possible answer would be points C, N and M.

-----------------

Problem 4

To name a plane, we can pick 3 points inside the plane that aren't collinear. One such possible answer is Plane ANC

We cannot label the plane as "plane ANX" because infinitely many planes pass through these collinear points. Think of the plane able to rotate like a propeller. So this is why we need 3 non-collinear points to uniquely define the plane.

-----------------

Problem 5

The points R, N, M and X are not in the same plane V. If we ignored point R, then the remaining points (N, M, X) are all in the same plane. However, the presence of R is what makes them not coplanar.

Think of points N, M and X being on the ground while point R is somewhere up in the air. Unfortunately the 2D diagram makes it tricky to show that R is above the plane.

So because those points are not in the same plane, we do not consider them coplanar.

-----------------

Problem 6

This is similar to problem 1. Technically there aren't any rays shown here, but we could focus on a subset of the line. Two possible answers are ray NM and ray NX

-----------------

Problem 7

Ray NM and ray NC can be glued together to form line CM. They point in completely opposite directions (eg: one points north, the other points south). Notice that rays NM and NC both start with the letter N to indicate that N is the endpoint (i.e. the part that doesn't go on forever).

Another possible answer would be ray NA and ray NX. They glue together to form line XA.

-----------------

Problem 8

There are 3 lines and they are:

  • Line XA
  • Line CM
  • Line RN

To name a line, all we need are two points that are on the line itself. A line has a characteristic of going on forever in both directions. So that's why we have the double arrow symbol \leftrightarrow overtop the line name.

Example: \overset{\longleftrightarrow}{\text{RN}} = \text{line RN}

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Light bulbs manufactured at a certain factory have a 3% probability of being defective. what is the probability that 5 out of a
lbvjy [14]

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. The probability that 5 out of a shipment of 30 will be defective is 0.001617.

<h3>What is Binomial distribution?</h3>

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

Where,

x is the number of successes needed,

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p is the probability of a single success, and

q is the probability of a single failure.

The probability of the bulb being defective is 3%(0.03) and the probability of the bulb not being defective is 97%(0.97).

Now, it is needed to be found that the probability that 5 out of a shipment of 30 will be defective can be written as,

P(x) = ⁿCₓ pˣ q⁽ⁿ⁻ˣ⁾

P(x=5) = ³⁰C₅ (0.03)⁵ (0.97)²⁵

P(x=5) = 0.001617

Hence, the probability that 5 out of a shipment of 30 will be defective is 0.001617.

Learn more about Binomial Distribution:

brainly.com/question/14565246

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How do i figure out the degrees?
liraira [26]

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  41°

Step-by-step explanation:

This problem involving the Law of Cosines has been mostly worked for you. The value of the cosine is the solution to the remaining one-step linear equation. The inverse cosine function (cos⁻¹ or arccos) is used to find the angle from the value of the cosine.

  -1125 = -1500·cos(A)

  cos(A) = -1125/-1500 = 3/4 . . . . . divide by -1500 (this is the one step)

  A = arccos(3/4) ≈ 41.4096°

The angle formed by the lines to the lampposts is about 41°.

__

<em>Additional comment</em>

If you find the angle using the ACOS( ) function of a spreadsheet, you will always get the result in radians. Most calculators offer the choice of units for angles, so be sure you set the mode appropriately.

In the calculator screenshot, there is a decimal point in the fraction to force the angle result to be displayed as a numerical value. Otherwise, this calculator shows cos⁻¹(3/4), which isn't terribly helpful.

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2 years ago
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