The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the inequality:
3 ≤ |x + 2| ≤ 6
Hence:
x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)
This gives:
x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
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Answer:
#16 = (0, -10)
#17 = (-18, -3)
Step-by-step explanation:
U wouldn't use the distance formula, you would need to use the Midpoint Formula, which is, M = (x1 + x2 / 2, y1 + y2 / 2). For #16, you plug in (4, -5) for M and 8 for x1 and 0 for y1, so the equation should look like this : (4, -5) = (8 + x2 / 2, 0 + y2 / 2). Then separate the equation to make it easier: 4 = 8 + x2 / 2 and the second equation : -5 = 0 + y2 / 2. So let's do the 1st equation, the first step would be to multiply the 2 to both sides. So the equation should look like this, 8 = 8 + x. Then subtract the 8 from both sides and you get 0 as your x. Now moving on to the 2nd equation, you multiply the 2 to both sides, and you get, -10 = 0 + y, as your equation, but since 0 won't affect it, -10 should be your y. Then just use these steps to solve #17, and your answer should be (-18, -3).
Answer:
check the attached picture
Step-by-step explanation:
Given function is 
.
Now we need to make a table of values for the function rule then graph the function.
We are free to plug any values of x like -3,-2,-1,0,1,2,3,... etc becaues domain of polynomial function is all real numbers.
Let's plug x=1 into given function to find the y-value
Hence the first point is (1,3).
Same way we can find few more points to complete the table then graph those points and connect them to get the final graph.
x y
-2 8
-1 5
0 4
1 5
2 8
Answer:
Step-by-step explanation:
Given that Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that each of their offspring will develop the disease is approximately 0.25.
Let X be the no of children having this disease out of 4 occasions
Then X has two outcomes and each trial is independent of the other trial
Hence X is binomial with n =4, and p = 0.25
a) 
b) 
c) 
since independent.
Answer:
here is the answer
Step-by-step explanation:
