Answer:
8.11 and 9 1/11
Step-by-step explanation:
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point (21, 13)
Point (3, 13)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formula]:
- [√Radical] (Parenthesis) Subtract:
- [√Radical] Evaluate exponents:
- [√Radical] Add:
- [√Radical] Evaluate:
Answer:
1,620/.60 = $2,700
step-by-step explanation:
Calculate the complement of the trade discount 100% - 40 = .60 •Calculate the list price $n Discount Rates EXAMPLE: The list price of the office equipment is $15,000. The chain discount is 20/15/10.Step 1. $15,000 X .20 =$3,000Step 2. $15,000-3,000=$12,000 X .15 = $1,800Step 3. $12,000-1,800 = $10,200 X.10 = $1,020Step 4. $10,000- 1,020 = 9,180 Net PriceCalculating Net Price Using Net Price Equivalent Rate EXAMPLE: The list price of office equipment is $15,000. The chain discount is 20/15/10. What is the net price? Step 1. Calculate each rates complement and convert to a decimal.100%-20 = 80% which is .8100%-15= 85% which is .85100% -10 = 90% which is .9Step 2. Calculate the net price equivalent rate. ( Do not round ).8 X .85 X .9 = .612 Net price equivalent rate. For each dollar you are spending about 60 cents.Step 3. Calculate the net price (actual cost to buyer) $15,000 X .612 = $9,180Step 1. Subtract each chain discount rate from 100% (find the complement) and convert each percent to a decimal.Trade Discount AmountList price x Trade discount rate = Trade discount amount $5,678 x 25% = $1,419.50Net Price List price -- Trade discount amount = Net Price
Answer: option <span>D) y=x, x-axis, y=x, y-axis</span>.
I first thought it was the option C) and I tried with it but it was wrong. This is how I dit it.
Option C step by step:
<span>1) Reflection over the x - axis => point with coordinates (a,b) is transformed into point with coordinates (a, -b)
2) Reflection over the line y = x => point with coordinates (a, -b) is transformed into point with coordinates (-b,a)
3) New feflection over the x - axis => (-b,a) transforms into (-b, -a)
4) New reflection over the line y = x => (-b,-a) transforms into (-a,-b)
Which shows it is not the option C).
Then I probed with option D. Step by step:
1) Reflection over the line y = x => (a,b) → (b,a)
2) Reflection over the x-axis => (b,a) → (b,-a)
3) Reflection over the line y = x => (b,-a) → (-a,b)
4) Reflection over the y-axis => (-a,b) → (a,b).
So, this set of reflections, given by the option D) transforms any point into itself, which proofs that the option D) is the right answer.
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