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3 years ago

What is the value of y?

Mathematics

2 answers:

irakobra [83]3 years ago

6 0

I think its d not sure

Len [333]3 years ago

4 0

30 degrees is the measure of y.

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Find the equation of the line that is perpendicular to -x+2y=11 and passes through the point (6,-5).

Serggg [28]

Step-by-step explanation:

m=-2

y+5=2(x-6)

y+5=2x-12

y=2x-17

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3 years ago

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Which expression represents the <br>phrase 4 times the sum of 9 and 6

Dominik [7]

It would be x=4(9+6)

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3 years ago

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1.3.12

jasenka [17]

Answer:

(0.5,-1.5)

Step-by-step explanation:

this is the numbers i got when I put it in...

m=( ${-\frac{1+0}{2} , \frac{-5+2}{2}$ )

(0.5,-1.5)

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3 years ago

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PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

2 years ago

EMERGENCY (NEED HEP NOW!!!)

diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

$4x - y = - 9 \\ 3x - 3y = 0$

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

$12x -3 y = - 27 \\ 3x - 3y = 0$

Subtract the current second equation from the first one.

$12x = - 27$

Divide through by 12:

$x = - \frac{27}{12} = - 2.25$

From the second equation we have:

$3x = 3y$

This implies that:

$x = y = - 2.25$

8 0

3 years ago