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2 years ago

Hola, ayudenme a hacer esto por fa, doy muchos puntos u,u

Mathematics

2 answers:

nikitadnepr [17]2 years ago

8 0

Answer:

de donde viene la hoja asi la investigo y te digo las respuestas :)

Step-by-step explanation:

sergiy2304 [10]2 years ago

6 0

Answer: Hi, help me do this by fa, I give a lot of points u,u

Step-by-step explanation:

You might be interested in

Help please and thank you

aksik [14]

Remember
$(a^b)^c=a^{bc}$
and
$\frac{x^a}{x^b}=x^{a-b}$

so

$\frac{(7^2)^5}{7^{-6}}=$
$\frac{7^{2*5}}{7^{-6}}=$
$\frac{7^{10}}{7^{-6}}=$
$7^{10-(-6)}=$
$7^{10+6}=$
$7^{16}$

the answer is D

5 0

3 years ago

Can someone pls help me

erica [24]

I would love to help you :)

So what do we know?:

We know that side A has a length of 25, and side B has a length of 21.

So that leaves us to find the length of side C correct?

Answer

Tbh I'm to lazy to explain how I got this and its mostly likely incorrect. but I think the answer is

(most likely incorrect LOL)

<u><em>IM SO SORRY IF I MADE YOU FAIL THE QUESTION SDNFKJSDFSDF</em></u>

5 0

2 years ago

Read 2 more answers

Find the quotient please

LenKa [72]

Answer:

-7.

Step-by-step explanation:

Fractions are division! If you don't know what a quotient is, It is basically a more complicated way of saying "find the answer by dividing." So we always divide the numerator (top number) by the denominator (bottom number). So we get 14÷-2 and we can see that -2 is a negative number, so remember that a positive times or divided by a negative is always a negative number. So therefore we get -7 as our quotient.

6 0

3 years ago

The 2008 Workplace Productivity Survey, commissioned by LexisNexis and prepared by WorldOne Research, included the question, "Ho

vitfil [10]

Answer:

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

Step-by-step explanation:

Let X be the number of hours a legal professional works on a typical workday. Imagine that X is normally distributed with a known standard deviation of 12.6.

The population standard deviation is

$\sigma = 12.6 \: hours$

A sample of 250 legal professionals was surveyed, and the sample's mean response was 9 hours.

The sample size is

$n = 250$

The sample mean is

$\bar{x} = 9 \: hours$

Since the sample size is quite large then according to the central limit theorem, the sample mean is approximately normally distributed.

The population mean would be the same as the sample mean that is

$\mu = \bar{x} = 9 \: hours$

The sample standard deviation would be

$s = {\frac{\sigma}{\sqrt{n} }$

Where is the population standard deviation and n is the sample size.

$s = {\frac{12.6}{\sqrt{250} }$

$s = 0.7969 \: hours$

Therefore, the sampling distribution of $\bar{x}$ is normal with a mean equal to 9 hours and a standard deviation of 0.7969 hours.

The population mean confidence interval is given by

$\text {confidence interval} = \mu \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sampling size, s is the sample standard deviation and is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 250 - 1 = 249

From the t-table at α = 0.025 and DoF = 249

t-score = 1.9695

$MoE = t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\\\MoE = 1.9695\cdot \frac{12.6}{\sqrt{250} } \\\\MoE = 1.9695\cdot 0.7969\\\\MoE = 1.569\\\\$

So the required 95% confidence interval is

$\text {confidence interval} = \mu \pm MoE\\\\\text {confidence interval} = 9 \pm 1.569\\\\\text {LCI } = 9 - 1.569 = 7.431\\\\\text {UCI } = 9 + 1.569 = 10.569$

The 95% interval estimate of the population mean $\mu$ is

LCL = 7.431 hours to UCL = 10.569 hours

8 0

3 years ago

Find the value of x when the triangle has 9 and 3

DENIUS [597]

Answer:

H²=h²+b²

H²=9²+3²

H²=81+9

H²=90

$\sqrt{90}$

5 0

2 years ago