<span><span><span><span><span>(<span>5+4</span>)</span><span>(2)</span></span>+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span><span>=<span><span><span><span><span>(9)</span><span>(2)</span></span>+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span><span>18+6</span>−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span>24−<span><span>(2)</span><span>(2)</span></span></span>−1</span></span><span>=<span><span>24−4</span>−1</span></span><span>=<span>20−1</span></span><span>=<span>19</span></span>
Answer:
Yes
Step-by-step explanation:
Since we are adding two polynomials
The sum will also be polynomial
The answer is 27 because 8-2=6 and 9-6=3 then 8*2=24 and 24+3=27
Fractions
We are going to be checking each statement in order to find which of them are correct:
<h2>5/6 < 6/8 - 5/6 is smaller than 6/8</h2>
We can see that in the drawing 3/8 is smaller than 5/6. Then this statement is false.
<h2>
4/6 < 5/8 - 4/6 is smaller than 5/8</h2>
We can see that in the drawing 5/8 is smaller than 4/6. Then this statement is false.
<h2>
2/6 = 3/8 - 2/6 is equal to 3/8</h2>
We can see that in the drawing 3/8 is bigger than 2/6. Then this statement is false.
<h2>
3/6 = 4/8 - 3/6 is equal to 4/8</h2>
We can see that in the drawing 4/8 is equal to 3/6. Then this statement is true.
<h2>
Answer: 3/6 = 4/8</h2>
Answer:

Step-by-step explanation:
Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.
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Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².
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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).
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Taken altogether, these factors give us the function ...
