Question

Tina has two bags of counters, Bag A and Bag B.

Answer 1

The probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Given that Tina has two bags of counters, Bag A and Bag B, and there are 5 red counters and 3 blue counters in bag A, while there are 4 red counters and 5 blue counters in bag B, to determine, if Tina takes at random a counter from each bag, the probability of obtaining each counter, the following calculation must be made:

• Bag A red counter = 5/8 = 0.625
• Bag A blue counter = 1 - 0.625 = 0.375
• Bag B red counter = 4/9 = 0.444
• Bag B blue counter = 1 - 0.444 = 0.555
• Two red = 0.625 x 0.444 = 0.2777
• Two blue = 0.375 x 0.555 = 0.2083
• One red and one blue = 1 - 0.2777 - 0.2083 = 0.5138

Therefore, the probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Learn more about probability in brainly.com/question/25638875