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kaheart [24]
3 years ago
9

What is the area of the original rectangle? A.8cm sq B.20cm sq C.25cm sq D.40cm sq

Mathematics
2 answers:
jasenka [17]3 years ago
7 0

A is the answer

You find the scale factor by doing 8÷1.6 which = 5

Then you do 25÷5=5

And then times 5 and 1.6 together to get 8cm sq

Bumek [7]3 years ago
4 0

Answer:

A. 8 cm sq

Step-by-step explanation:

Find the scale factor

new width/original width

8/1.6=5

calculate length of original rectangle

new length/scale factor

25/5=5cm

Find area of original rectangle

A=l×w

A=1.6×5=8cm²

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oee [108]

Answer:

x=5.5

Step-by-step explanation:

LN and KM intersect and are in the same rectangle, which makes them the same line essentially. Set 49 equal to 6x+16 and then solve to get x by itself.

5 0
3 years ago
Read 2 more answers
Kareem wrote the values shown below.
grandymaker [24]

Answer:

Option D is correct.

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

Step-by-step explanation:

Floor function states that the greatest integer that is less than or equal to x.

It is represented by: \lfloor x \rfloor

Ceiling function states that the least integer that is greater than or equal to x.

It is represented by: \lceil x \rceil

As per the statement:-

Kareem wrote the values show below:

\lceil 3.2 \rceil,  \lfloor 2.7 \rfloor,  \lceil 2.9 \rceil and \lfloor 4.8 \rfloor.

by definition:

\lceil 3.2 \rceil = 4

\lfloor 2.7 \rfloor = 2

\lceil 2.9 \rceil=3

\lfloor 4.8 \rfloor = 4

From the given options only pair which is equivalent is:

\lfloor 4.8 \rfloor  and \lceil 3.2 \rceil

7 0
3 years ago
A bus driver pays all tolls, using only nickels and dimes, by throwing one coin at a time into the mechanical toll collector.
lutik1710 [3]

Answer: a) An = An-1 + An-2

b) 55ways

Step-by-step explanation:

a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.

Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that

An = 5n cents

Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;

An-1 = 5( n-1)

Case 2: using a dime which is two 5 cents, the number of ways is given as;

An-2 = 5(n-2)

Summing up the number of ways, we have

An = An-1 + An-2

From the relation,

If n= 0, Ao= 1

n =1, A1= 1

b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)

From the relation, we have that

Ao = 1

A1 = 1

An =An-1 + An-2

Ao = 1

A1 = 1

A2 = A1+Ao = 1+1= 2

A3 = A2 + A1 = 3

A4 = A3+A2=5

A5=A4+A3=8

A6=A5+A4=13

A7 =A6+A5 = 21

A8= A7+A6= 34

A9= A8+A7= 55

So there are 55ways to pay 45cents.

4 0
3 years ago
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Marysya12 [62]
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You know the vertex is (1, 3) because you match the pattern to
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which has its vertex at (h, k).

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3 years ago
Find f(x) and g(x) so that the function can be described as y= f(g(x)) y=9/x^2 + 2
fgiga [73]
\left[y \right] = \left[ 0\right][y]=[0] I hope helping with u
6 0
3 years ago
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