6(x + 2) = 2(x + 10)

2 answers:

4 0

6(x + 2) = 2(x + 10)
6x + 12 = 2x + 20
6x - 2x = -12 + 20
4x = 8
x = 8/4
x = 2

3(y - 4) + 2 = 5y - 28
3y - 12 + 2 = 5y - 28
3y -10 = 5y - 28
3y - 5y = 10 - 28
-2y = -18
y = -18/-2
y = 9

5(2z - 3) - 3z = 3(z + 3)
10z - 15 - 3z = 3z + 9
7z - 15 = 3z + 9
7z - 3z = 15 + 9
4z = 24
z = 24/4
z = 6

UNO [17]3 years ago

3 0

YOU CAN ALWAYS DOUBLE CHECK BY PLUGGING THE VARIABLE VALUE INTO THE PROBLEM!
6(x + 2) = 2(x + 10)
6x + 12 = 2x + 20 (Distribute both sides)
6x + 12 = 2x + 20
-12 -20 (Subtract 12 from both sides)
6x = 2x + 8 (The result of subtracting)
-2x -2x (Subtract 2x from both sides)
4x = 8
/4 /4 (Divide 4 from both sides)
X = 2
——
3(y - 4) + 2 = 5y - 28
3y - 12 + 2 = 5y - 28 (Distribute)
3y - 12 + 2 = 5y - 28 (Add -12 + 2)
3y - 10 = 5y - 28
+10 +10 (Add 10 to both sides. The sign in front of a # follows it)
3y = 5y - 18
-5y -5y (Subtract 5y from both sides)
-2y = -18 (Divide -2 from both sides)
/-2 /-2
Y = 9
——
5(2z - 3) - 3z = 3(z + 3)
10z - 15 - 3z = 3z + 9 (Distribute from both sides)
7z - 15 = 3z + 9 (Combine like terms, left side)
+15 +15 (Add 15 to both sides)
7z = 3z + 24
-3z -3z (Subtract 3z from both sides)
4z = 24
/4 /4 (Divide by 4 to both sides)
Z = 6

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