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Aneli [31]
2 years ago
8

Solve the simultaneous equations 5x+2y=25 5x-y=10

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
4 0

<em>5x + 2y = 25;</em>

<em>5x + 2y = 25;5x - y = 10;</em>

5x + 2y = 25;

5x = 10 + y;

(10 + y) + 2y = 25;

5x = 10 + y;

10 + 3y = 25;

5x = 10 + y;

3y = 15;

5x = 10 + y;

y = 5;

5x = 10 + y;

y = 5;

5x = 10 + 5;

y = 5;

5x = 15;

y = 5;

x = 3.

Answer: (3; 5).

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The mean is calculated by adding up all of the given numbers and dividing by the number of numbers.

Lets, for ease of understanding, say that the first three number were 64...

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Now, lets solve for the mean where 'x' is the unknown fourth number and 128 is the mean. (since, the answer said that when the fourth number was added the mean, 64, was doubled '64*2=128')

128=(64+64+64+x)/4
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subtract 192 from both sides
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Now lets double check our work.

Mean=(64+64+64+320)/4=512/4=128

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