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Oduvanchick [21]
2 years ago
6

I need help I’ll give branliest

Mathematics
2 answers:
valkas [14]2 years ago
5 0

Answer:

B

Step-by-step explanation:

we know the thickness is x, so the sides are 3+2x and 4+2x

then we use foil:

(3+2x)(4+2x)=12+6x+8x+4x^2=4x^2+14x+12

we know the area is 15

4x^2+14x+12=15

4x^2+14x-3=0

So it is B

katovenus [111]2 years ago
3 0

Answer:

A

Step-by-step explanation:

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7 1/4 boxes weigh total of 66 7/8 what does one box weigh
Ray Of Light [21]

Answer:

68.875 / 7.25 = 9 1/2 pounds

Step-by-step explanation:

6 0
3 years ago
Find the 95th term of the arithmetic sequence 4,-5,-14
mestny [16]

Answer:

Step-by-step explanation:

d = - 9

a = 4

n = 95

tn = a + (n - 1)*d

t95 = 4 + (94)*(-9)

t95 = 4 -846

t95 = - 842

7 0
3 years ago
grandpa has some cows and ducks in his farm. all in all there are 8 heads and 26 legs, how many cows and ducks are in there? sol
butalik [34]

Answer:

5 cows  and 3 ducks

okay well there are 8 heads and each animal has a head meaning that there are a total of 8 organisms in total. Cows have 4 legs and ducks have 2. Lets say that c is cows and d is ducks. You would have the equations ...

c+d=8

4c+2d=26  

well d techniacally = 8-c, so plug in (8-c) for the value of d

4c+2(8-c)=26.      Distribute to get

4c+16-2c

and then add like terms. Soy ou would get

2c+16=26.

then just isolate the variable but subtracting 16 from both sides and dividing 2 on both sides. The answer you would get is that c=5 so there are 5 cows. Plug in 5 for c so you get 5+d=8 and tadaaaa you subtract 5 from both sides to get that there are 3 ducks.

hope this helps :)

7 0
4 years ago
How to find the perimeter of the triangle
Sliva [168]

Answer:

A. 26.2

Step-by-step explanation:

To find the perimeter of the triangle, you have to find the distances of all three lines and add them up.

<u>Line AB</u>

Let's start off by finding the distance of line AB.

We will use the formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point A is (-2,5) and Point B is (4,-3).

To substitute the values, it will get to d = \sqrt{(4--2)^{2}+(-3-5)^{2}} which in other words is d = \sqrt{(4+2)^{2}+(-3-5)^{2}}.

Now we have to solve the parenthesis to get d = \sqrt{(6)^{2}+(-8)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{36+64}.

Now we have to simplify the square root to d = \sqrt{100}. In other words, that is d = 10.

Line AB = 10

<u>Line BC</u>

Now let's find the distance of line BC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point B is (4,-3) and Point C is (0,-6).

To substitute the values, it will get to d = \sqrt{(0-4)^{2}+(-6--3)^{2}} which in other words is d = \sqrt{(0-4)^{2}+(-6+3)^{2}}.

Now we have to solve the parentheses to get d = \sqrt{(-4)^{2}+(-3)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{16+9}.

Now we have to simplify the square root to d = \sqrt{25}. In other words, that is d = 5.

Line BC = 5.

<u>Line AC</u>

Now let's fine the distance of line AC.

We will use the same formula, d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Point A is (-2,5) and Point C is (0,-6).

To substitute the values, it will get to d = \sqrt{(0--2)^{2}+(-6-5)^{2}} which in other words is d = \sqrt{(0+2)^{2}+(-6-5)^{2}}.

Now we have to solve the parentheses to get d = \sqrt{(2)^{2}+(-11)^{2}}.

Now we have to solve the exponents which would get to d = \sqrt{4+121}.

Now we have to simplify the square root to d = \sqrt{125}. In other words, that is d = 5\sqrt{5}. To round that, d = 11.2.

Line AC = 11.2.

<u>Perimeter of Triangle ABC</u>

Perimeter of Triangle ABC = Line AB + Line BC + Line AC.

Perimeter of Triangle ABC = 10 + 5 + 11.2

Perimeter of Triangle ABC = 26.2

Hope this helped! If not, please let me know <3

3 0
3 years ago
Write 2.75 as a mixed number and as an improper fraction.<br> Write your answers in simplest form.
Stolb23 [73]
2 3/4 11/4 hope this helps
4 0
3 years ago
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