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Oduvanchick [21]
3 years ago
6

I need help I’ll give branliest

Mathematics
2 answers:
valkas [14]3 years ago
5 0

Answer:

B

Step-by-step explanation:

we know the thickness is x, so the sides are 3+2x and 4+2x

then we use foil:

(3+2x)(4+2x)=12+6x+8x+4x^2=4x^2+14x+12

we know the area is 15

4x^2+14x+12=15

4x^2+14x-3=0

So it is B

katovenus [111]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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yawa3891 [41]
Answer


If one of your options are six then choose it
6 0
3 years ago
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
4 years ago
What are these numbers from least to greatest: 2.8, 2.75, 3.125, 2.2repeating
Anton [14]
2.2(repeating), 2.75, 2.8, 3.125
8 0
3 years ago
Read 2 more answers
Solve each pair of equations by substituting <br><br><br> 2x + y = 3<br> 4x + 3y = 1
Usimov [2.4K]
Step: Solve
2
x
+
y
=
3
for y:
2
x
+
y
=
3
2
x
+
y
+
−
2
x
=
3
+
−
2
x
(Add -2x to both sides)
y
=
−
2
x
+
3

Step: Substitute
−
2
x
+
3
for
y
in
4
x
+
3
y
=
1
:
4
x
+
3
y
=
1
4
x
+
3
(
−
2
x
+
3
)
=
1
−
2
x
+
9
=
1
(Simplify both sides of the equation)
−
2
x
+
9
+
−
9
=
1
+
−
9
(Add -9 to both sides)
−
2
x
=
−
8
−
2
x
−
2
=
−
8
−
2
(Divide both sides by -2)
x
=
4

Step: Substitute
4
for
x
in
y
=
−
2
x
+
3
:
y
=
−
2
x
+
3
y
=
(
−
2
)
(
4
)
+
3
y
=
−
5
(Simplify both sides of the equation)

Answer:
x
=
4
and
y
=
−
5
6 0
3 years ago
Read 2 more answers
Evaluate q-r if q= -14 and r=-6
Blababa [14]

Answer:

- 8

Step-by-step explanation:

substitute q = - 14 and r = - 6 into the expression

q - r

= - 14 - (- 6)

= - 14 + 6

= - 8

5 0
2 years ago
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