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sergeinik [125]
2 years ago
9

The median for the data: 10,12,15,16,8, 7 is

Mathematics
2 answers:
Lerok [7]2 years ago
8 0

Answer:

11

Step-by-step explanation:

7,8,10,12,15,16

12+10=22÷2=11

ANTONII [103]2 years ago
8 0

Answer:

11

Step-by-step explanation:

10, 12, 15, 16, 8, 7

Write the numbers in increasing order:

7, 8, 10, 12, 15, 16

The median is the middle number if there is an odd number of numbers.

Here we have an even number of numbers (6), so the median is the arithmetic mean (average) of the two middle numbers.

median = (10 + 12)/2 = 22/2 = 11

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On my brother's 14th birthday, he was 160 cm tall. Within exactly one year, his height increased by 6%. How tall was he on his 1
Charra [1.4K]

Answer:

170 cm

Step-by-step explanation:

160+.06*160=160+9.6=169.6

8 0
3 years ago
Help i will give 20 points<br> And brainlist
marysya [2.9K]

Answer:

for #14, x=10

Step-by-step explanation:

in the graph, 6x = 5x +10 so if x was 10 it would be 60 = 60 so x = 10

5 0
3 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
Can someone please explain to me how to solve this equation?
Nikolay [14]

Answer:

first of all erase what u have written

Step-by-step explanation:

<h2>Q: 25-(3x+5)=2(x+8)+x</h2>
  • 25-3x-5=2x+16+x
  • 20-6x=16
  • 6x=4
  • x=2/3
6 0
3 years ago
16 divided by 1 and 7/9
stellarik [79]

Answer:

Alright well the Answer to this question is

9 Hope this helps :)

Step 1: Convert to mixed number 1 7/9 into an improper fraction first by multiplying the denominator, by the whole number

Step 2: Then add the numerator, to get the new numerator. Place the New numerator over the old denominator

16 divided by 16 and 9

To divide by fraction, multiply by it's reciprocal 16(9/16)

Cancel the common factor of 16, then simplify 1/1 9/1 which gives u

9 Hope all this helps :)



Step-by-step explanation:


8 0
3 years ago
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