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VARVARA [1.3K]
3 years ago
8

Shari sent a total of 64 text messages to 4 friends. each friend received the same number of text messages. which number

Mathematics
1 answer:
Inga [223]3 years ago
4 0
Each freinds received 16 texts in total
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A rectangle has a length of x+7 and a width of x-3. write and expression that represents the AREA of the rectangle.
Lyrx [107]

Answer:

A = x^2 + 4x -21

Step-by-step explanation:

L = x+7

W = x-3

A = L*W

A = (x+7)(x-3)

A = x^2 + 4x - 21

6 0
3 years ago
Mr. Clifton was preparing for his upcoming birthday party. He ordered 51 white balloons and 47 red balloons. As he walked to his
Andrej [43]

Answer:

28 i think

Step-by-step explanation:

51+47=98

98-12 the ones that flew away that takes it to 86

86/3 the 3 balloons buntch than is 28

p.s. i mght of got some equations wrong but this is what i got

4 0
3 years ago
There are 37 cans of pineapple on each shelf at food mart if there are 7 shelves of pineapple estimate the number of cans pineap
Luba_88 [7]

Answer:

260

Step-by-step explanation:

7 shelves containing 37 cans of pineapples each would give you 259 cans of pineapple. Then, round to the nearest ten would give you 260.

7 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
2 years ago
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
Xelga [282]
The opposite angles of a quadrilateral are supplementary so you can set them equal to 180.

If there was more information given then i could find the exact values.

Hope this helps :)
8 0
3 years ago
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