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Sloan [31]
3 years ago
14

determine whether each statement is always, sometimes, or never true. an absolute value function of the form f(x)=/x+a/+b has ex

actly one x intercept.

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

<u>Answer-</u>

<em>The statement that f(x) = |x+a| + b has exactly one x-intercept is sometimes correct.</em>

<u>Solution-</u>

It solely depends on b, whether the function will have one or two or zero x intercept.

This plot of the given function, f(x) = |x+a| + b will be the basic absolute value graph i.e V shape, with vertex translated to (-a, b), instead of origin.

1-  If b is zero, the graph will have exactly one x-intercept, at x= -a

2- If b is positive, the whole graph will be above the x-axis, hence it will have no x-intercepts.

3- If b is negative, the graph will be below the x-axis, hence it will have two x-intercepts.

∴ The statement is sometimes true.

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80 POINTS!!!!!!
Lera25 [3.4K]
Plz dont be mean to me i just wanna understand and also its the blue line for answer 1
6 0
3 years ago
A bag of marbles contains 6 bluemarbles, 2 yeloow marbles, 4 red marbles, and 1 green marble. What is the [robability of reachin
irina [24]

Answer:

The probability of picking a yellow marble is 2/13

Step-by-step explanation:

First of all, we need to know the total number of marbles that are in the bag. To do this, we will have to add up all the marble colors together.

This will give us 6 + 2 +4+ 1 = 13 marbles in total.

The next step is to find the number of yellow marbles in the bag.

We can get this from the question. There are 2 yellow marbles in the bag.

The probability of selecting a yellow marble can be obtained by dividing the number of yellow marbles by the total number of marbles in the bag

This will give us 2/13.

Therefore, the probability of picking a yellow marble is 2/13

5 0
3 years ago
A FEW MATH QUESTIONS ! PLEASE EXPLAIN ANSWERS ! (:
7nadin3 [17]

answers

1) 70

2) 3,840

3) 24

4) 72


<u>Explanation</u>

Q1

The surface area of a cone is given by;

S.A = 2Πrl + Πr²

Where r is the radius of the base and l is the lateral height.

Πr² = area of the base = 20 in²

2Πrl = Area of the lateral surface

         = 2.5 × 20

          = 50

Area of the cone = 50 + 20

                            = 70 in²

Q2

The sides of the Pythagorean triangle with legs of 12 and 16.

The 3rd side will be;

c = √(12² + 16²)

  = √400 = 20

Volume = 12 × 16 × 20

              = 3,840

Q3

The volume of a cone is given by;

volume = 1/3 Π r² h

This shows that the volume of a cone is a third the volume of the cylinder.

∴ Volume of the cylinder = 12 × 3

                                            = 24 ft³

Q4

The volume of any regular figure is;

Volume = base area × height

When the dimensions area usually 3. Let these dimensions be x, y and z.

∴ volume  = x × y × z = 9

  Doubling the dimensions;

Volume = 2x × 2y × 2z = 2 × 2 × 2 × 9

             = 8 × xyz = 8 × 9

             = 72 ft²



3 0
3 years ago
Read 2 more answers
Please come answer ASAP!!!<br> 5 - n divided by 3 = 4 what is the value of n?
Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

-n = -27

Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

7 0
3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
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