If the solution exists, y=y....
3x+2=-x/4+1 make everything have a common denominator of 4...
(12x+8)/4=(-x+4)/4 now multiply both sides by 4
12x+8=4-x add x to both sides
13x+8=4 subtract 8 from both sides
13x=-4 divide both sides by 13
x=-4/13
x≈-0.31 and the only pair in your choices having an x value close to that is:
(-0.3, 1.1)
Answer:
The function is increasing on the interval [-2,1]
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area of the figure = Are of square with side 8 in + 2 times the area of one triangle with base (8 - 5 = 3) 3 in and height 4 in
Answer:
Both of these examples are wrong. You cannot add/subtract integers and square roots together, however, you could add square roots together if they have the same number under the square root. For example, 2 - 2√6 will stay as 2 - 2√6 because they aren't like terms. 25 + 5√5 + 5√5 + 5 = 30 + 10√5 because 25 + 5 = 30 and 5√5 + 5√5 = 10√5. We can add 5√5 and 5√5 together because they have the same number under the square root. If we were to compute √2 + √3, we would just leave it as is because they don't have the same number under the square root.
Answer: -2
Step-by-step explanation:
When x = 1, y = -2.
Hope it helps <3
