3 years ago

How to find the value of a relation function

1 answer:

Katen [24]3 years ago

8 0

Their is only one y for each x. you could also use the vertical line test, you could use the graphing calculator.

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REY [17]

$y = \frac{1}{2x^{2} - 4}$
$0 = \frac{1}{2x^{2} - 4}$
$0(2x^{2} - 4) = (2x - 4)(\frac{1}{2x^{2} - 4})$
$0(2x^{2}) - 0(4) = 1$
$0 - 0 = 1$
$0\neq1$

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3 years ago

elena55 [62]

Answer:

28,980

Step-by-step explanation:

69 x 420 = 28,980

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3 years ago

masha68 [24]

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3 years ago

scZoUnD [109]

I believe the answer is C

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3 years ago