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Eva8 [605]
2 years ago
10

Given the conditional relative frequency table by column, what does the 0. 14 represent? Given that a student is a 10th grader,

there is a 14% chance he or she has a job. Given that a student has a job, there is a 14% chance he or she is a 10th grader. 14% of the students surveyed are 10th graders who have a job. 14% of the students are 10th graders.
Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Conditional relative frequency is the ratio of the the value of somthing with the total value for a set in data table. The option A is the correct option which is a student is a 10th grader, there is a 14% chance he or she has a job.

Given information

In the given table,

There is 10th grade students are with 0.14 has job and 0.86 has no job in total 1.

There is 11th grade students are with 0.25 has job and 0.75 has no job in total 1.

There is total students are with 0.20 has job and 0.80 has no job in total of 1.

<h3>Conditional relative frequency-</h3>

Conditional relative frequency is the ratio of the the value of somthing with the total value for a set in data table.

The column two gives the data of the 10th grade students. In the total of 1, 0.14 students has jobs and these students belongs to 10th grade. 0.14 is 14 percent of the number 1. Thus the 14 percent of 10 grade students has job.

Thus the option A is the correct option which is a student is a 10th grader, there is a 14% chance he or she has a job.

Learn more about the conditional relative frequency  here;

brainly.com/question/3444575

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Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

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The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

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Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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