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Llana [10]
2 years ago
11

The conference room can hold fewer than 100 people What is the equation for this question

Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

C = conference room capacity

we can write something along the lines of C < 100, namely C can hold is less than 100.

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Read 2 more answers
United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res
Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so n = 200.

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So \pi = 0.0995.

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find P(X < 18), with \pi = 0.0995, n = 200. We can use a binomial probability calculator, and we find that:

P(X < 18) = 0.2927.

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0
2 years ago
A cab charges $1.75 for the first mile and $0.25 for each additional mile. Write and solve an inequality to determine how many m
Margaret [11]
A. 1.75+0.25x<15;x,53miles

sorry, i could not put in the or equal to signs
                       
4 0
3 years ago
2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for
nadezda [96]

The question is incomplete:

1. A cosmetologist must double his/her salary before the employer con realize any profit from  his/her work,  Miss, Mead paid Miss, Adams $125,00 per week to start.

2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for  services if Miss. Mead is to realize $50.00 profit on her work? (Conditions on salary are the same  as in problem 1)  

ODS

a. $275.00 b. $325.00 c. $250.00 d. $300.00

Answer:

d. $300.00

Step-by-step explanation:

Given that a cosmetologist must double her salary before the employer can realize any profit from  his/her work, for Miss. Mead to realize $50.00 profit on her work, you would have to determine the amount that doubles the salary of the cosmetologist and add the $50 needed as profit:

Salary= $125*2=$250

$250+$50= $300

According to this, the answer is that for Mead to realize $50.00 profit on her work, Miss. Brown must take $300.

4 0
3 years ago
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