<span>f(x)=x^2+6x+3
=(1/2.6)^2=3^2=9
f(x)=(x2^+6x+9)+3-9
=(x+3)^2-6</span>
30 = arc BC / 2
arc BC = 2(30)
arc BC = 60
answer
D. 60
To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The <span>spherical bubble gum ball is at the bottom
- The radius of the cone is 1.5 inches, and its height is 3 inches.
- The diameter of the bubble gum ball is 0.5 inches.
2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
Vs=4</span>πr^3/3
r is the radius (r=0.5 inches/2=0.25 inches)
Vs=4π(0.25 inches)^3/3
Vs=0.065 inches^3
3. The volume of the cone is:
Vc=πr^2h/3
r is the radius of the cone (r=1.5 inches)
h is the height (h= 3 inches)
Vc=π(1.5 inches)^2(3 inches)/3
Vc=7.06 inches^3
W<span>hat is the closest approximation of the volume of the cone that can be filled with flavored ice?
Vt=Vc-Vs
Vt</span>≈7.00 inches^3
Answer:
10
Step-by-step explanation:
3 x 5 = 15 so 2 x 5 = 10
Answer: 72 cm
Step-by-step explanation:
The diameter is twice the radius, in other words just multiply the radius by 2.
36*2= 72 (You could also just add 36 to itself). I hope this helps!
