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Reil [10]
3 years ago
15

To make a ribbon and bow for a hat Stacey needs 5/6 yard of black ribbon and 2/3 yard of red ribbon. How much total ribbon dose

she need
Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0
7/9 because all you need to do is add them
luda_lava [24]3 years ago
3 0
Answer:7/9

Explanation:First find the common denominator then add them.

5/6 + 2/3= 7/9
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Dont get this help asap!
algol [13]

Answer:

Step-by-step explanation:

It is a rectangle, so both sides are equal. Thus 2x+6=5x-9

SOLVE, SUBTRACT 2x

6=3x-9   THEN ADD 9

15=3x    THEN divide by 3

5=x

Plug in x to either side 2(5)+6, to get side length of 16

Then area of a rectangle is lengthxwidth=AREA

substitute what you know     16(y)=48

Divide by 16, thus y=3

7 0
2 years ago
You have 6 reindeer, Rudy, Jebediab, Ezekiel, Lancer, Gloopin, and Balthazar, and you want to have 5 fly your sleigh. You always
Anna71 [15]
You can arrange your reindeer 30 different ways.
5 0
3 years ago
Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose?
butalik [34]
Assuming this Fence enclosment will be in the shape of a rectangle we will use the equation used to find the area of a rectangle, b×h=a

Using this formula we then must pick out factors used to create, in which the perimeter will add up to 20

·5,5,5,5 (25)
·8,2,8,2 (16)
·6,4,6,4 (24)


using this we can learn<span> that the maximum area that can be exclosed by this is 25, because the 2 perimiter lengths that define this rectangle would be 5 and 5.

</span>b(5)×h(5)=25(a)

therefore, your answer is 25 Units

-I hope this is the answer you are looking for feel free to post your questions here on brainly in the future
3 0
3 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
KIM [24]
To determine the total distance traveled by an object in constant speed, just multiply the speed by the time. So, for the car, the total distance traveled is,
                               distance by car = (20 m/s)(5s) = 100 m
For decelerating object, the distance traveled is,
                          distance = Vt - (at^2)/2
For the truck,
         distance by truck = (20 m/s)(10s) - (2m/s^2)((10s)^2)/2 = 100 m

Relatively, both have traveled the same distance. 
7 0
3 years ago
How do i become smarter in math class and im in 8th grade
12345 [234]

Answer:

I'm in 8th grade too, It's easy to pass math, Just take a screenshot of your hw, then submit it, My math teacher doesn't care if I just submit it.

Step-by-step explanation:

5 0
3 years ago
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