75+ 15x ≥ 140
⇒ 15x ≥ 140-75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3
Final answer: x ≥ 4 1/3~
Since she needs 3 1/2 for 5, and you need to find one batch, get 3 1/2 and divide it by 5. Change 3 1/2 to an improper fraction (7/2). Now use KCS (keep change switch) Keep the 7/2, change division to multiplication, and switch 5/1 to 1/5. (7/2)•(1/5)
Answer:
Answers may vary but will most likely be close to 2.
Step-by-step explanation
- Given:
first test:38%
second test:76%
SIMULATION FIRST TEST
Randomly select a 2-digit number.
If the digit is between 00 and 35 then you passed the test,else you did not pass the test.
SIMULATION SECOND TEST
Randomly select a 2-digit number.
if the digit is between 00 and 75 then you passed the test,else you did not pass the test.
SIMULATION TRIAL
Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.
Record the number of trials needed to pass the first or second test.
Repeat 20 times and take the average of the 20 recorded number of trials
(what is the sum of recorded values divided by 20).
Note:you will most likely obtain a result of about two trials needed.
i think A is the answer and why cant you just click the little ask for help button?
If the greater integer is m, then the smaller integer must be (m-3) because the integers are 3 units apart on a number line. It cannot be in front of m, because m is the greater so it must be behind m meaning it is 3 units less. Product is the technical term for the result of a multiplication problem so m(m-3) = 108 would be the answer.
Final Answer: m(m-3) = 108
