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solmaris [256]
2 years ago
8

Tionna's car expenses include car insurance and fuel. Tionna's parents agree to pay a certain percent of her car expenses. The c

ost of car insurance is the same every month, but the cost of fuel depends on the d, number of miles she drives. The expression (0.10d+60)(1−a) represents how much Tionna must pay toward her monthly car expenses.
Which statement is correct?


The expression 1−a represents the percent of car expenses Tionna's parents pay each month, and 60 represents the cost of fuel.

The expression 1−a represents the percent of car expenses Tionna must pay each month, and 60 represents the cost of fuel.

The expression 1−a represents the percent of car expenses Tionna's parents pay each month, and 60 represents the cost of car insurance.

The expression 1−a represents the percent of car expenses Tionna must pay each month, and 60 represents the cost of car insurance.
Mathematics
1 answer:
viva [34]2 years ago
5 0

Answer:

C

Step-by-step explanation:

"The expression 1−a represents the percent of car expenses Tionna's parents pay each month, and 60 represents the cost of car insurance."

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The domain of f(x)= (2/3)^x is all negative numbers true or false
Salsk061 [2.6K]
False, probably. cause (2/3)^1 is defined
4 0
3 years ago
A man is 6 feet 3 inches tall. The tip of his shadow touches a fire hydrant that is 13 feet 6 inches away. What is the angle of
Natalija [7]

well, since a foot is 12inches, 6' 3" will just be 6.25' and 13' 6" will be 13.5'.

Check the picture below.

Make sure your calculator is in Degree mode.

8 0
2 years ago
If a warehouse received 250 orders in April and 300 in May, what was the percentage of increase in orders from April to May? (Th
erik [133]
300/250 = 6/5

1/5 = 20%

You are correct, well done.
7 0
3 years ago
Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

6x-y-4=0

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\  \end{gathered}

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

6y+x+18=0

5 0
1 year ago
System of equations <br> X+3y=73<br> X+y=27
Scrat [10]
Steps:
1. Change x + y= 27 into y=mx+ b form
2. Subtract x on both sides
Y= -x + 27
3. Substitute the y in x + 3y= 73 for -x + 27

X + 3(-x + 27) = 73
X + -3x + 81= 73
-2x + 81= 73
4. Now subtract 81 on both sides
-2x=-8
5. X= 4
6. Now solve for y
7. Now substitute the x in x + y= 27 for 4
8. 4 + y= 27
9. Subtract 4 on both sides
10. Y= 23
11. Your answer is: x= -4 and y= 23 or (-4,23)
8 0
3 years ago
Read 2 more answers
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