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ss7ja [257]
4 years ago
10

A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea

ch question and all questions are answered independently. (a) What is the probability that the student answers more than 20 questions correctly? (b) What is the probability that the student answers fewer than 5 questions correctly?
Mathematics
1 answer:
weqwewe [10]4 years ago
7 0

Answer:

a)  8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

where

n= total number of questions= 25

p= probability of getting a question right = 1/4

then

a) P(x=n) = p^n = (1/4)²⁵ = 8*88*10⁻⁶ ( 0.00088 %)

b) P(x<5)= F(5)

where F(x) is the cumulative binomial probability distribution- Then from tables

P(x<5)= F(5)= 0.2137 (21.37%)

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Answer:

462 paths from A to B

Step-by-step explanation:

The question is incomplete. However, a possible question is to determine the number of possible paths on the grid map.

The first step is to represent the grid map itself. (See attachment 1)

From the question, we understand that:

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There are a several number of ways to navigate through. However, one possible way is in attachment 2

In attachment 2,

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And we have:

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The number of possible paths (N) is then calculated as:

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Substitute values for N and U

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