Answer:
W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)
W1 - W2 = 0
Step-by-step explanation:
Work done in stretching a spring is given by 1/2ke^2
Where, k is force constant and e is extension
e1 = 30cm - 20cm = 10cm
W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules
e2 = 40cm - 30cm = 10cm
W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules
W1 = W2 = 50k Joules provided W1 and W2 have equal force constant
Therefore, W1 - W2 = 0
Answer:
=144*8/2.5
=1152/2.5
=460.8
Step-by-step explanation:
there you go
Marcia dissolved 1 kg of salt in 3 litres of water.
Bobby dissolves 2 pounds of salt in 7 pints of water
2.11 pints = 1 litre
7 pints = 7/2.11
= 3.32 litre
1 pound =0.45 kg
2 pound = o.45*2 kg
= 0.9 kg
So we find that Bobby is dissolving 0.9kg of salt in 3.32 litre of water
Marcia is dissolving 1 kg of salt in 3 litres of water.
3-7, 4-8, 2-6, and 1-5 are all corresponding.
