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DerKrebs [107]
3 years ago
9

PLEASE HELP ME WITH THIS!!

Mathematics
1 answer:
gregori [183]3 years ago
3 0
The last one is the answer. GD is similar to MJ, and DE is similar to JK. While DE is similar to ML as well, it is more so to JK because they are facing the same way
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What's the Error? Explain the error. Find the correct solution.<br>19 + (-31) = 12​
Alex

Answer:

The answer is incorrect because 12 should be negative not positive.

Step-by-step explanation:

1. 19 + -31 = - 12

2. Twelve is negative because if you were to start off at -31 and add 19 the answer would remain negative since -31 in a sense is "bigger" than 19. You would need more of a positive number to make -31 positive such as 40.

40+ -31 = 9

5 0
3 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
3 years ago
PLEASE HELP
Inessa [10]

Answer:

the measure of the missing length is 3 mi

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
What is the 10th, 75th, and nth term in the sequence 6, <br> 15,24,33,42?
Nat2105 [25]
The nth term is 9n-3. The 10th term is 87 and the 75th term is 642.
5 0
3 years ago
Suppose the number of dropped footballs for a wide receiver, over the course of a season, are normally distributed with a mean o
inessss [21]
The z-score is the number of standard deviations away from the mean. We first subtract the actual score from the mean, then divide the difference by the standard deviation. In this case, our actual score is 13, so we subtract from the mean of 16, then divide by the SD of 2
(13 - 16) / 2 = -1.5
8 0
3 years ago
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