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DerKrebs [107]
3 years ago
9

PLEASE HELP ME WITH THIS!!

Mathematics
1 answer:
gregori [183]3 years ago
3 0
The last one is the answer. GD is similar to MJ, and DE is similar to JK. While DE is similar to ML as well, it is more so to JK because they are facing the same way
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Explain how to change a negative exponent to a positive one
VikaD [51]

Answer:

Step-by-step explanation:

Negative exponents in the numerator get moved to the denominator and become positive exponents. Negative exponents in the denominator get moved to the numerator and become positive exponents.

plz mark as brainliest

7 0
3 years ago
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Heather has $500 in her savings account. She withdraws $20 per week for gas. Write an equation Heather can use to see how many w
marusya05 [52]
500-20x=200 is the equation
5 0
2 years ago
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Can someone please help?
Alika [10]

Answer:

A. mean 71.33, median 86, mode 90 90 100 100, range 55

B. mean 79.41, median 36.5, mode 90, range 60

c. mean 73.16, median 2, mode 75 75 80 80, range 45

Step-by-step explanation:

mean is the average so add all numbers then divide by the number of number

mode is the number that is often seen

range subtract the smallest from largest or the other way around

median the middle number when lined all number from less to biggest  

4 0
3 years ago
Point M is located at (4,6) on a coordinate grid. Point M is translated 8 units to thr left and 9 units down to create point M'.
nata0808 [166]
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!

We have the point 4,6. 4 is the x, and 6 is the y.

Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.

Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.

So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!

The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²

Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.

So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.

So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²

Solving it out, we first need to work within the parenthesis. Can you solve it?

Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²

8²= 64
9²= 81

64+81 = 145.

So, the distance between point M and point M' would be 145 units

Hope this helps!

If it does not, please let me know so i can try to help!

4 0
3 years ago
Find The art length of a sector with an area of 8 square units.
frez [133]
\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
\cfrac{2880}{16\pi }=\theta \implies \boxed{\cfrac{180}{\pi }=\theta }\\\\
-------------------------------\\\\

\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =\frac{180}{\pi }\\
r=4
\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}
\\\\\\
\boxed{s=4}

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.
6 0
3 years ago
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