The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:
y² + 15y + 56 = (y + 7)(y + a)
y² + 15y + 56 = y² + (7 + a)y + 7a
We can now compare the coefficient of the like terms, either the one with y or the one without y, and find the value of a.
15 = 7 + a; a = 8
OR
56 = 7a; a = 8
Second factor is (y + 8)
1. 2(4) - 4y = 20
8 -4y = 20
8-8 -4y = 20 - 8
-4/-4y = 12/-4
y = -3
Answer:
x = the wight of the large box
y = the weight of the small box
A delivery of 3 large boxes and 2 small boxes has a total weight of 73 kilograms.
3x + 2y = 73
A delivery of 8 large boxes and 4 small boxes has a total weight of 177 kilograms.
8x + 4y = 177
by solving the system of equations
3x + 2y = 73
8x + 4y = 177
we find
x = 15.5 kg
y = 13.25 kg
the large box weights 15.5 kg.
the small box weights 13.25 kg.
