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2 years ago

5

1) There are 43 girls and 25 boys in the Valley View Middle School chorus. What is the ratio of girls to boys? 43 to 25, or 43:2

5 o 25 to 43, or 25:43

1 answer:

Arturiano [62]2 years ago

6 0

Answer:

Oh gosh. Im not positive but I think it would be 43:25. Please dont get mad at me if its wrong!

Step-by-step explanation:

I am so sorry if its wrong but im not very sure :-(

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Please help me I will give thanks and points!

makkiz [27]

1.31, 1.4, and 1.44.

Hope I helped☺☺

6 0

3 years ago

(GIVING BRAINLIEST!!)

melomori [17]

Answer:

your answer is gonna be "A" if you want to type 1/14 into the calculator.

8 0

3 years ago

Read 2 more answers

Pls only do this if yk it because i’m giving correct answer brainliest! :))

Leno4ka [110]

Answer:

$x=2+\frac{1}{2}\sqrt[]{21}$

or

$x=2-\frac{1}{2}\sqrt{{21}$

Step-by-step explanation:

$4x^2-16x-26=-21$

Add 21 on both sides.

$4x^2-16x-26+21=-21+21$

$4x^2-16x-5=0$

a=4

b=-16

c=-5

$x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

$x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)} }{2(4)}$

$x=\frac{16\frac{+}{}\sqrt[]{256+80} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{336} }{8}$

$x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21} }{8}$

$x=\frac{16\frac{+}{}2*2\sqrt[]{21} }{8}$

$x=\frac{16\frac{+}{}4\sqrt[]{21} }{8}$

---------------------------------------------------------------------------

$x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}$

$x=2+\frac{1}{2}\sqrt[]{21}$

---------------------------------------------------------------------------

$x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}$

6 0

2 years ago

Read 2 more answers

Jeremy measured the room to be 10 feet long and 4.5 feet wide. He plans to purchase carpet for the entire room. The carpet cost

Andreyy89

Answer:

$205.73

Step-by-step explanation:

First we find the square area,

multiply 10 by 4.5 and we get 45

we convert feet to meters by dividing it by 3.281

45/3.281=13.71533

we the multiply 13.71533 by 15 to get the total price

we get 205.72996 and round it to 205.72

5 0

2 years ago

Can someone help me please

goldenfox [79]

Answer:

$1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}$

Step-by-step explanation:

The applicable rule is ...

$x^{\frac{m}{n}}=\sqrt[n]{x^m}$

It works both ways, going from radicals to frational exponents and vice versa.

The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.

7 0

3 years ago