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Allisa [31]
3 years ago
10

Solve this please 16x = 64^x + 4 the x plus 4 the 4 is an exponet but i cant make it look like one here are the multi choice x =

−12
x = −2
x = 2
x = 12
Mathematics
2 answers:
Lena [83]3 years ago
5 0

Answer:

-12

Step-by-step explanation:

16^×=64^×+4

4^2×=4^3(×+4)

since the root are the same you cut it it.

2× =3×+12

2x-3x=12

-x=12

divide both side by -1

x=-12

Delvig [45]3 years ago
3 0

Answer:

I think it's -12.

Step-by-step explanation:

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Length = 18 and 1/2 inches = 37/2

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Answer:

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step

That is (\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4} Calvin's step is the correct step.Because this is the correct way to do simplify the rational expression. And also because Nadine made a blender mistake in her operations in step

Step-by-step explanation:

Given that Nadine and Calvin are simplifying the expression (StartFraction r Superscript negative 5 Baseline s Superscript negative 3 Baseline Over r Superscript 8 Baseline s Superscript negative 2 Baseline EndFraction) Superscript negative 4

Their expression can be written as below

(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}

Nadine's first step is to simplify the expression is to raise the numerator and denominator to the power of 4 to get StartFraction r Superscript negative 20 Baseline s Superscript negative 12 Baseline Over r Superscript 32 Baseline s Superscript 8 Baseline EndFraction

That is \frac{r^{20}s^{12}}{r^{-32}s^8}

Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4

That is r^{-13}s^{-1}

Now simplify the given expression to check whose step is correct:

(\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}

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=(r^{-5-8}s^{-3+2})^{-4}

=(r^{-13}s^{-1})^{-4}

Therefore (\frac{r^{-5}s^{-3}}{r^8s^{-2}})^{-4}=(r^{-13}s^{-1})^{-4}

Therefore Calvin's first step is to simplify the expression is to apply the quotient of powers to get (r Superscript negative 13 Baseline s Superscript negative 1 Baseline) Superscript negative 4 is the correct step.

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