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3 years ago

11

True or FalseIn order for a function to be one-to-one, no two independent variable values may yield the same value of the depend

ent variable

2 answers:

lara31 [8.8K]3 years ago

7 0

Its true. no independent variable may yield the same thing as a dependent variable.

Harman [31]3 years ago

4 0

Dependent variables are dependent on the independent variable ie
f(x)=8x
f(x)=demendent variable
x=independent
in order for the fn to be 1-to-1, no 2 independent variables may yeild the sam edepend variables
true
that is the same thing as
for every input, you get exatly 1 output

answer is TRUE

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How does remote work relate to taking an online class or being an online student (fully online or hybrid)?

Svetach [21]

Answer:

Answered

Step-by-step explanation:

Online courses are those classes which are delivered entirely online. Students study via web cam, chat rooms and smart boards. Whereas hybrid learning is a combination of both online learning and traditional in class learning. Remote work is working away from the work place at your own comfort and choice of location.

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3 years ago

Find the value of x that will make A||B<br> 9x + 4<br> 5x + 20<br> x = [?]

mrs_skeptik [129]

9x + 4= 5x + 20 (alternate interior angles)

9x-5x =20-4

4x = 16

x= 16/4

x= 4

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2 years ago

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8 0

3 years ago

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The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas

saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by $s(t) = -t^3+3t^2+7t +4$ , where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

$s(t) = -t^3+3t^2+7t +4$

Derivate w.r.t. time,

$v(t)=s'(t) = -3t^2+6t+7$

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

$x=-\frac{b}{2a}$

Where, a=-3, b=6 and c=7

$t=-\frac{6}{2(-3)}$

$t=-\frac{6}{-6}$

$t=1$

As 1 lie between interval [0,4]

Substitute t=1 in the function,

$v(t)= -3(1)^2+6(1)+7$

$v(t)= -3+6+7$

$v(1)=10$

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0

2 years ago

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What is -9x-(2x/-3) When x equals 7

yuradex [85]

$-9x- \frac{2x}{-3}$

$-9*(7) - \frac{2*7}{-3}$

$9*7 = 63$

$\frac{2*7}{-3} = \frac{14}{-3}$

Apply the fraction rule : $\frac{a}{-b} = - \frac{a}{b}$

$= - \frac{14}{3}$

$-63-( -\frac{14}{3} )$

Apply rule - ( - a) = a

$-63+ \frac{14}{3}$

Convert element to fraction :

$63 = \frac{63}{1}$

$-\frac{63}{1} + \frac{14}{3}$

Find the LCD 1*3 = 3

$- \frac{63*3}{3}+ \frac{14}{3}$

$\frac{-3+63+14}{3} = \frac{-175}{3}$

<span>Apply the fraction rule : $\frac{a}{-b} = - \frac{a}{b}$ </span>

$= - \frac{175}{3}$

hope this helps!

4 0

3 years ago