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Evaluate for x = -10 and y = 6 3x + xy - 4y

Setler [38]

We plug in -10 as x and 6 as y. We get -30 - 60 - 24 = -90 - 24 = -114
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Hope this helps!
==jding713==

8 0

3 years ago

PLEASE HELP 20 POINTS + BRAILYEST!!!

zubka84 [21]

Answer:

4 in

Step-by-step explanation:

The Pythagorean theorem tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides. Solve this problem by writing that relationship using the given information, then solving the equation for the missing side.

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5² = 3² + ?²

25 = 9 + ?² . . . . . simplify

16 = ?² . . . . . . . . . subtract 9

4 = ? . . . . . . . . . . . take the square root

The missing length is 4 inches.

4 0

3 years ago

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In an elevator that has a weight limit of 1800 pounds and w represents the amount of weight in pound what should my inequality s

sasho [114]

Answer: w has to be less than or equal to 1800 hundred so this (w<1800) but with a less than or equal to sign

Step-by-step explanation:

8 0

3 years ago

What are the domain and range of f(x) = (1/6)x + 2? domain: ; range: {y | y > 0} domain: ; range: {y | y > 2} domain: {x |

Trava [24]

Sir you posted question and answer? or are providing examples of preferred format?

7 0

3 years ago

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1)Convert the following binary numbwers into decimal number(only a,b,c,f,i)

kozerog [31]

Answer:

a) 3₁₀

b) 6₁₀

c) 7₁₀

f) 19₁₀

i) 181₁₀

Step-by-step explanation:

Binary to Decimal Conversion (Positional Notation Method)

Multiply each digit by the base (2) raised to the power dependent upon the position of that digit in the binary number.
Sum all the values obtained for each digit.
Express the number as a decimal number by placing subscript 10 after it.

For a binary number with 'n' digits:

The right-most digit is multiplied by 2⁰
The left-most digit is multiplied by $\sf 2^{n-1}$

For example, to convert the binary number 111001₂ into a decimal:

$\begin{array}{ c c c c c c}1 & 1 & 1 & 0 & 0 & 1\\\downarrow & \downarrow & \downarrow & \downarrow & \downarrow & \downarrow \\2^5 & 2^4 & 2^3 & 2^2 & 2^1 & 2^0\\\end{array}$

Multiply each digit by the base (2) raised to the power as indicated above and sum them:

$=(1 \times 2^5)+(1 \times 2^4)+(1 \times 2^3)+(0 \times 2^2)+(0 \times 2^1)+(1 \times 2^0)$

$= 32+16+8+0+0+1$

$= 57$

Finally, express as a decimal number ⇒ 111001₂ = 57₁₀

Question (a)

$\begin{aligned}\implies 11_2 & = (1 \times 2^1)+(1 \times 2^0)\\& = 2+1\\& = 3\end{aligned}$

Therefore, 11₂ = 3₁₀

Question (b)

$\begin{aligned}\implies 110_2 & = (1 \times 2^2)+(1 \times 2^1)+(0 \times 2^0)\\& = 4+2+0\\& = 6\end{aligned}$

Therefore, 110₂ = 6₁₀

Question (c)

$\begin{aligned}\implies 111_2 & = (1 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =4+2+1\\& = 7\end{aligned}$

Therefore, 111₂ = 7₁₀

Question (f)

$\begin{aligned}\implies 10011_2 & =(1 \times 2^4)+(0 \times 2^3)+ (0 \times 2^2) +(1 \times 2^1)+(1 \times 2^0)\\& =16+0+0+2+1\\& = 19\end{aligned}$

Therefore, 10011₂ = 19₁₀

Question (i)

$\phantom{)))}10110101_2 \\\\=(1 \times 2^7)+(0 \times 2^6)+(1 \times 2^5)+(1 \times 2^4)+(0 \times 2^3)+ (1 \times 2^2) +(0 \times 2^1)+(1 \times 2^0)\\\\=128+0+32+16+0+4+0+1\\\\= 181$

Therefore, 10110101₂ = 181₁₀

8 0

2 years ago

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