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2 years ago

Can someone pls help me with this question?

Mathematics

1 answer:

bogdanovich [222]2 years ago

7 0

Answer:

I think your anwser would be 4 im not sure

Step-by-step explanation:

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An electrician charges $40 to come to your house.She also charges $55for each that she works. The electrician charges you total

shusha [124]

Answer:

Step-by-step explanation:

First, write an equation. 55x+40=190.

X represents the hours the electrician works. The 55 represents the $55 that she charges for each hour she works. The +40 for the $40 that was the price just to come to your house. The 190 is the total cost. Now, solve that equation.

55x+40=190

55x=150

x=2.72727272...

So the answer is 2.727 hours. It can be rounded as needed or turned into a decimal, 2 8/11.

5 0

3 years ago

Anna is planning a big birthday bash for her sixteenth birthday party and wants to invite as many people as possible but she has

Hitman42 [59]

P=(500-100)÷6.50
p=400÷6.50
p=6.15

7 0

3 years ago

Read 2 more answers

From a circular cylinder of diameter 10 cm and height 12 cm are conical cavity of the same base radius and of the same height is

Nataliya [291]

<h3>Volume of the remaining solid = 628 cm^2</h3>

<h3>Whole surface area = 659.4 cm^2</h3>

Step-by-step explanation:

Now, Given that:-

Diameter (d) = 10 cm

So, Radius (r) = 10/2 = 5cm

Height of the cylinder = 12cm.

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= > \pi \times {5}^{2} \times 12 {cm}^{3} = 300\pi {cm}^{3}$

Radius of the cone = 5 cm.

Height of the cone = 12 cm.

$slant \: height \: of \: the \: cone \: = \sqrt{ {h}^{2} + \: {r}^{2} }$

$= > \sqrt{ {5}^{2}+{12}^{2} } cm \: = 13cm$

Volume of the cone = 1/3 *πr^2h

$= > \frac{1}{3} \pi \times {5}^{2} \times 12 {cm}^{3} = 100\pi {cm}^{3}$

therefore, the volume of the remaining solid

$= 300\pi {cm}^{3} - 100\pi {cm}^{3} \\ = 200 \times 3.14 {cm}^{3} = 628 {cm}^{3}$

Curved surface of the cylinder =

$2\pi \: rh \: = 2\pi \times 5 \times 12 {cm}^{2} \\ = 120\pi {cm}^{2} .$

$curved \: surface \: of \: the \: cone \: = \pi \: rl \\ = \pi \times 5 \times 13 {cm}^{2} \\ = 65\pi {cm }^{2} \\ area \: of \: (upper)circular \: base \: \\ of \: cylinder \: = \\ = \pi \: {r}^{2} = \pi \times {5}^{2}$