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AURORKA [14]
3 years ago
6

A theater wants to build movable steps that they can use to go on and off the stage. They want the steps to have enough space in

side so they can also be used to store props. How much space is inside the steps? Give an exact answer (do not round).

Mathematics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

0.045

Step-by-step explanation:

khan

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What is x???????need help
gogolik [260]

Answer:

100 degrees

Step-by-step explanation:

The angle x is opposite the angle that is 100 degrees.

Since they are opposite each other, they are vertical angles.

This means that they are congruent, or equal to each other.

Therefore,

x=100

x is 100 degrees

7 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
Square of a standard normal: Warmup 1.0 point possible (graded, results hidden) What is the mean ????[????2] and variance ??????
LenaWriter [7]

Answer:

E[X^2]= \frac{2!}{2^1 1!}= 1

Var(X^2)= 3-(1)^2 =2

Step-by-step explanation:

For this case we can use the moment generating function for the normal model given by:

\phi(t) = E[e^{tX}]

And this function is very useful when the distribution analyzed have exponentials and we can write the generating moment function can be write like this:

\phi(t) = C \int_{R} e^{tx} e^{-\frac{x^2}{2}} dx = C \int_R e^{-\frac{x^2}{2} +tx} dx = e^{\frac{t^2}{2}} C \int_R e^{-\frac{(x-t)^2}{2}}dx

And we have that the moment generating function can be write like this:

\phi(t) = e^{\frac{t^2}{2}

And we can write this as an infinite series like this:

\phi(t)= 1 +(\frac{t^2}{2})+\frac{1}{2} (\frac{t^2}{2})^2 +....+\frac{1}{k!}(\frac{t^2}{2})^k+ ...

And since this series converges absolutely for all the possible values of tX as converges the series e^2, we can use this to write this expression:

E[e^{tX}]= E[1+ tX +\frac{1}{2} (tX)^2 +....+\frac{1}{n!}(tX)^n +....]

E[e^{tX}]= 1+ E[X]t +\frac{1}{2}E[X^2]t^2 +....+\frac{1}{n1}E[X^n] t^n+...

and we can use the property that the convergent power series can be equal only if they are equal term by term and then we have:

\frac{1}{(2k)!} E[X^{2k}] t^{2k}=\frac{1}{k!} (\frac{t^2}{2})^k =\frac{1}{2^k k!} t^{2k}

And then we have this:

E[X^{2k}]=\frac{(2k)!}{2^k k!}, k=0,1,2,...

And then we can find the E[X^2]

E[X^2]= \frac{2!}{2^1 1!}= 1

And we can find the variance like this :

Var(X^2) = E[X^4]-[E(X^2)]^2

And first we find:

E[X^4]= \frac{4!}{2^2 2!}= 3

And then the variance is given by:

Var(X^2)= 3-(1)^2 =2

7 0
3 years ago
A jewelry box is b2 inches long, 3c2 inches wide, and 2c1 inches tall. Which of the following are correct? Select ALL that apply
Mariulka [41]

9514 1404 393

Answer:

  B, F

Step-by-step explanation:

The volume is the product of the dimensions:

  V = LWH

  V = (b^2)(3c^2)(2c^1) = (3·2)(b^2)(c^(2+1))

  V = 6b^2·c^3 . . . . . matches B

__

For b=3 and c=2, the volume is ...

  V = 6(3^2)(2^3) = 6(9)(8)

  V = 432 . . . . cubic inches . . . . matches F

6 0
3 years ago
Which expression is another way to write 3 radical 125 x^4?
9966 [12]

The given expression is

3\sqrt{125x^4}

We have to write it in a different way and for that, we have to check the factors of 125 and x^4 .

And factors of 125 are 25 and 5.

3\sqrt{25*5*(x^2)^2}

Radical 25 equals to 5 and radical x^4   is  x^2.

So we will get

3*5x^2 \sqrt{5} = 15x^2 \sqrt{5}

And that's the another way to write the given expression .


3 0
3 years ago
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