Answer:
They would be at where they are for hours after.
Explanation:
Although the motion of the water is appearing to be traveling East, making Johnny think that the wave is actually pushing on the boat East bound, what is really happening here is that the motion of the particles of water is actually moving up and down that propagate to the East. Therefore, the wave would only be pushing the boat up and down, not toward land.
Answer:
The vertical distance traveled is 3.18 m.
Explanation:
In order to find the vertical distance traveled by a body in free fall motion, starting from rest to a velocity of 7.9 m/s. For this purpose, we use Newton's third equation of motion,
2as = Vf² - Vi²
where,
a = g = 9.8 m/s²
s = vertical distance = Δy = ?
Vf = final velocity = 7.9 m/s
Vi = initial velocity = 0 m/s
Therefore,
2(9.8 m/s²)Δy = (7.9 m/s)² - (0 m/s)²
Δy = (7.9 m/s)²/(2)(9.8 m/s²)
<u>Δy = 3.18 m</u>
Answer:
#_time = 7.5 10⁴ s
Explanation:
In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.
t =
where t_p is the person's own time in an immobile reference frame,
let's calculate
we assume that the speed of the space station is constant
t_ = 0.99998666657 s
therefore the time change is
Δt = t - t_p
Δt = 1 - 0.9998666657
Δt = 1.3333 10⁻⁵ s
this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s
#_time = 1 / Δt
#_time =
#_time = 7.5 10⁴ s
Fnet=Fapp
manet=Fapp
Solve for m
m=Fapp/anet
m=100N/4m/s^2
so mass must equal 25kg
Assuming this is a frictionless surface
Red shift in the light coming towards us from other galaxies.