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2 years ago

The atomic number of magnesium is 12. This means that its nucleus must contain

Physics

2 answers:

Lena [83]2 years ago

3 0

12 protons and 12 electrons

Marina86 [1]2 years ago

3 0

The atomic of magnesium is 12 this means that its nucleus 12 protons and no electrons are not in the nucleus

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Which equation best expresses the first law of thermodynamics, assuming Q is heat, U is internal energy, and W is work?

devlian [24]

The first law of thermodynamics is expresses by

D. ΔU=Q-W

which means change in internal energy of system = Heat added to system minus work done by the system

All are expressed in Joules.

This law is based on principle of conservation of energy.

5 0

3 years ago

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If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the g

oee [108]

Answer:

Explanation:

According to Boyle's law for constant temperature of gas Pressure is inversely proportional to the volume of gas.

$PV=nRT$

$PV=constant$

$P\propto \frac{1}{V}$

if Pressure is tripled then

$P\times V_1=3P\times V_2$

$V_2=\frac{V_1}{3}$

Volume becomes one-third of original volume

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2 years ago

I REALLY NEED HELP WITH PHYSICS ASAP!!!<br>Vf^2 = v0^2 + 2a (xf - x0)<br><br><br>Solve for a

ELEN [110]

Answer:

a. solve for a

$vf ^{2} = vo ^{2} + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2} - vo ^{2} \\ a = \frac{vf^{2} - vo^{2} }{2(xf - xo)} \\ a = \frac{vf ^{2} - vo ^{2} }{2xf - 2xo}$

I hope I helped you ^_^

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2 years ago

The distance between Pluto and the Sun is 39.1 times more than the distance between the Sun and Earth. Calculate the time taken

german

Answer:

Explanation:

Given

Distance between Pluto and sun is 39.1 times more than the distance between earth and sun

According to Kepler's Law

$T^2=kR^3$

where k=constant

T=time period

R=Radius of orbit

Suppose $R_1$ is the radius of orbit of earth and sun

so Distance between Pluto and sun is $R_2=39.1\cdot R_1$

$T_1$ and $T_2$ is the time period corresponding to $R_1$ and R_2[/tex]

$(T_1)^2=k(R_1)^3---1$

$(T_2)^2=k(R_2)^3---2$

divide 1 and 2

$(\frac{365}{T_2})^2=(\frac{R_1}{39.1})^3$

$T_2^2=365^2\times 39.1^3$

$T_2=89239.67\ Earth\ days$

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2 years ago

What stage do most stars spend the majority of their lives in?

Anna007 [38]

It a stage known as the "Main Sequence" stage. Stars achieve nuclear stability at this point and remain in this stage until the end of their lives.
Have a nice day!

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2 years ago

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