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matrenka [14]
3 years ago
6

What is the value of the 4 in the number 27.43? write your answer as a fraction

Mathematics
1 answer:
aniked [119]3 years ago
5 0

Answer:

4 tenths or 4/10

Step-by-step explanation:

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Find the measure of angle X in the figure below
alexandr1967 [171]

Answer:

50 degrees

Step-by-step explanation:

65 times 2=130

180-130=50

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What is 14.79 as a rounded number​
Alex_Xolod [135]

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15

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Regular hexagon ABCDEF is inscribed in circle O. Find the measure of each arc and angle.
inessss [21]

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Measurement of angle ABC: 120

Measurement of arc ACE: 240

Measurement of arc AB: 60

Step-by-step explanation:

I got it right on my test

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2 years ago
What is the right-hand limit of as x approaches f(x) = x/x-5 as x approaches 5?
Ber [7]

Answer:

+\infty

Step-by-step explanation:

The expression for the right hand limit of f(x) is:

f = \frac{x+\epsilon}{x + \epsilon - 5}

The expression can be simplified with some algebraic handling:

f = \frac{1}{\frac{x+\epsilon-5}{x+\epsilon} }

f = \frac{1}{1-\frac{5}{x+\epsilon} }

Let be x = 5, as \epsilon is approaching zero, f is positive and becomes bigger, diverging to +\infty.

7 0
3 years ago
Someone help I don't know what the diameter or radius is​
Elenna [48]
<h3><u>Answer:</u></h3>

52.38 inch² & 261.90 inch²

<h3><u>Step-by-step explanation:</u></h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3><u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>

\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}

\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}

5 0
3 years ago
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