All categories

2 years ago

Solve 6,445 step by step

Mathematics

1 answer:

sergeinik [125]2 years ago

4 0

$\: \: \: \: \: \:$

<h2>Rewrite the decimal</h2>

$= \frac{1289}{200}$

<h2>hope it helps</h2>

see the attachment for explanation

You might be interested in

Sum 2 5/8 + 4 1/8 = ?

Lostsunrise [7]

Answer:

6 6/8 OR 6 3/4

Step-by-step explanation:

2 5/8 +4 1/8

6 6/8

SImplify= 6 3/4

4 0

3 years ago

Read 2 more answers

A company manufacturing company small solid plastic cubes .They use the expression s3 to find the volume of plastic needed to ma

DanielleElmas [232]

Yes, Luis is correct.
If s is equal to the the side length, then in the problem, s is equal to 8 millimeters. 8 x 3 is equal to 24, which would equate to 24 cubic millimeters.

4 0

3 years ago

In each diagram, line p is parallel to line f, and line t intersects lines p and f. Based on the diagram, what is the value of x

ololo11 [35]

X would be 84 degrees, since its corresponding angle would be worth 84.
Hope this helped!

4 0

3 years ago

What is the exact circumference of a circle with a radius of 17 millimeters?

anzhelika [568]

The equation of a circumference is 2 $\pi$ r. Since we know that r=17, we plug that into the formula, and get an answer of C. 34

7 0

3 years ago

Read 2 more answers

PLEASE HELP I NEED THIS ASAP Find the vertex of y=x^2-7x+4

Goshia [24]

Answer:

$\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

Step-by-step explanation:

$y=x^2-7x+4\\\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=ax^2+bx+c\:\mathrm{is}\:x_v=-\frac{b}{2a}\\\mathrm{The\:parabola\:params\:are:}\\a=1,\:b=-7,\:c=4\\x_v=-\frac{b}{2a}\\x_v=-\frac{\left(-7\right)}{2\cdot \:1}\\\mathrm{Simplify}\\x_v=\frac{7}{2}\\\mathrm{Plug\:in}\:\:x_v=\frac{7}{2}\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}\\y_v=\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4\\$

$\mathrm{Simplify\:}\left(\frac{7}{2}\right)^2-7\cdot \frac{7}{2}+4:\quad -\frac{33}{4}\\y_v=-\frac{33}{4}\\Therefore\:the\:parabola\:vertex\:is\\\left(\frac{7}{2},\:-\frac{33}{4}\right)\\\mathrm{If}\:a0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}\\a=1\\\mathrm{Minimum}\space\left(\frac{7}{2},\:-\frac{33}{4}\right)$

6 0

3 years ago