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3 years ago

Distributive Property Using GCF 25 + 30

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

1,25

5,5

1,30

2,15

3,10

5,6

The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

5(5+6).

This has the same value but it is just written differently.

Have a wonderful day! :D

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Write an equation for ben is 5 years older than john. the sum of john's age and twice ben's age equals 46. how old is john?

GrogVix [38]

X represents John's age
Ben = x+5
John = x

x+2(x+5)=46
use the distributive property for 2(x+5)

x+2x+10=46
combine like terms

3x+10=46
subtract 10 from each side

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divide both sides by 3

x=12

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Step-by-step explanation:

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3 years ago

If the chick grows at a rate of 4.8 grams/day and weighs 53.8 grams on day 4, how much did the chick weigh (in grams) the day it

Makovka662 [10]

Answer:

Step-by-step explanation:

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3 years ago

According to the World Health Organization (WHO) Child Growth Standards, the head circumference for boys at birth is normally di

Elena L [17]

Answer:

$z = \frac{X -\mu}{\sigma}$

This z score tell to us how many deviations we are below or above the mean for a given normal distribution.

For the case of Eddie we got:

$z= \frac{33.2-34.5}{1.3}= -1$

And for the case of Sue we got:

$z = \frac{32.7-33.9}{1.2}= -1$

So then for both cases we see that Eddie and Sue are 1 deviation below the true mean for each gender so then the best conclusion for this case would be:

C.They are the same size relative to other children of the same sex.

Step-by-step explanation:

We can define the random variable X as the head circumference for boys at birth and we know that the distribution for X is given by:

$X\sim N(\mu = 34.5, \sigma=1.3)$

Similarly we can define the random variable Y as the head circumference for boys at birth and we know that the distribution for Y is given by:

$Y\sim N(\mu = 33.9, \sigma=1.2)$

And we know that Eddie was born with 33.2 cm and Sue with 32.7 cm for the head circumference . Since we are interested to determine which child's head circumference is smaller relative to other children of the same sex, we can use the z score formula given by this formula:

$z = \frac{X -\mu}{\sigma}$

This z score tell to us how many deviations we are below or above the mean for a given normal distribution.

For the case of Eddie we got:

$z= \frac{33.2-34.5}{1.3}= -1$

And for the case of Sue we got:

$z = \frac{32.7-33.9}{1.2}= -1$

So then for both cases we see that Eddie and Sue are 1 deviation below the true mean for each gender so then the best conclusion for this case would be:

C.They are the same size relative to other children of the same sex.

5 0

3 years ago