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ella [17]
3 years ago
11

How do you solve 3(15.9 - 3.9) Step by step? I need help

Mathematics
2 answers:
N76 [4]3 years ago
5 0

Answer:

36

Step-by-step explanation:

3(15.9 - 3.9)

3 · (15.9 - 3.9)

3(15.9) - 3(3.9)

47.7 - 3(3.9)

47.7 - 11.7

36

mote1985 [20]3 years ago
4 0

Answer:

I believe the answer is 15

Step-by-step explanation:

15.9 - 3.9 (line up the decimals correctly)

then subtract it and you get 12.0

add 12.0 + 3 (under the 2)

12.0

+3

and you get 15 as your answer :)

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160 divided by 9 = the amount of trucks.

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100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
  • Grade of 60, with a weight of 30%.
  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
  • Average of $51,834, with a weight of \frac{10}{13}

Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

  • Average of $14.84, with a weight of \frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}
  • Average of $10.76, with a weight of \frac{4}{7}

Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

5 0
3 years ago
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