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2 years ago

Need help with my practice for a test please give awnser and show your work so i know how to do :)

Mathematics

2 answers:

docker41 [41]2 years ago

7 0

Answer:

Step-by-step explanation:

2 * 2 = 4u² (area of the central square)

2 * 2 : 2 = 2u² (area of one congruent triangle)

4 + 2 + 2 = 8u²

(u = units)

Naddik [55]2 years ago

6 0

Answer:

Step-by-step explanation:

first we need to calculate the area of the square: A = 2^2=4

After that we calculate the are of the area of isosceles triangle: A=1/2*2*2=2

so the total area is 4+2+2=8 ( because we have 2 isosceles triangles )

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Use the equation
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3 years ago

Help please!!!!!!!!!

In-s [12.5K]

ANSWER

EXPLANATION

For a matrix A of order n×n, the cofactor $C_{ij}$ of element $a_{ij}$ is defined to be

$C_{ij} = (-1)^{i+j} M_{ij}$

$M_{ij}$ is the minor of element $a_{ij}$ equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.

Here, we have

$C_{11} = (-1)^{1+1} M_{11} = M_{11}$

M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.

$\begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \end{aligned}$

Since the determinant of a 2×2 matrix is

$\det\left( \begin{bmatrix} a & b \\ c& d \end{bmatrix} \right) = ad-bc$

it follows that

so $C_{11} = M_{11} = 24$

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3 years ago

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