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oksian1 [2.3K]
3 years ago
10

Help I need it asap questions in second pic

Mathematics
2 answers:
dedylja [7]3 years ago
6 0
Your answer should be D
garri49 [273]3 years ago
3 0
The answer more then likely is D!
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Which one is greater 26% or 0.3
aleksandrvk [35]

Answer:

<h2>0.3 is greater</h2>

Step-by-step explanation:

The only way to compare these is to get them into the same format. Then, we will see which is larger. The way to convert a decimal to a percent is to move the decimal 2 places to the right.

0.3 = 30%

30% > 26%

8 0
3 years ago
R<br> S<br> Q<br> (3x + 5)<br> (9x – 17)<br> T<br> find x
Oxana [17]

Answer:

x=1

Step-by-step explanation:

3 x 1=3 3 +5=8 9 × 1 =9 9- 17=8

8 0
3 years ago
Find the length of the line segment shown. Round your answer to the nearest tenth.
Marina86 [1]

Answer:

d=10

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step 1: Define endpoint coordinates

(2, 5)

(-6, -1)

Step 2: Substitute and Evaluate

d=\sqrt{(-6-2)^2+(-1-5)^2}

d=\sqrt{(-8)^2+(-6)^2}

d=\sqrt{64+36}

d=\sqrt{100}

d=10

8 0
3 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
4 years ago
So, I have a question if anyone can answer soon.
Sonja [21]

Answer:

You're right must be a different problem

Step-by-step explanation:

You know this, but just to verify:

1. Find Common Denominator:

6 15/21 - 6 7/21

2. Subtract

6 15/21 - 6 7/21 = 8/21 feet

7 0
3 years ago
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