Find the solution of this system of two linear equations using substitution 11x+3y=103 and y =3x+1

1 answer:

8 0

11x+3y=103 and y=3x+1.

11x+3(3x+1)=103 -----> plug in (3x+1) for y in the first equation. You will want to distribute the 3 to the 3x+1 to get something that looks like:

11x+9x+3=103 ------> now you want to combine like terms

20x+3=103 ---> subtract 3 from both sides
20x=100 ----> divide both sides by 20
x=5

y=3(5)+1 ---> I like to plug in this to the equation that already has y isolated. 3*5 is 15, add 1 and you find that y=16.

(5, 16) will be your final answer (:

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