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Masja [62]
2 years ago
9

Mr. Aba builds a circular patio with a diameter of 12 feet. He covers the patio with paving stones. The cost of the paving stone

s is $10.50 per square foot. To the nearest dollar, how much do the paving stones cost.
Mathematics
2 answers:
Anettt [7]2 years ago
8 0

Answer:

395.85

Step-by-step explanation:

If the diameter is 12, then the radius must be 6. Following the formula of pi: 2 * pi * radius, our result is 37.7. 37.7 * 10.50 is 395.85

I really hope this helps. My memory of circles and pi isn't the best.

inn [45]2 years ago
6 0
Answer is: 1,187.518
I’m 1000% sure that this correct
I have done this question with other people! Hope this helped
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Answer:

a) 99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b) 99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

4​% rate of disk drive failure in a year.

This means that 96% work correctly, p = 0.96

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk​ drive, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 2

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984

99.84% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

b. If copies of all your computer data are stored on four independent hard disk​ drives, what is the probability that during a​ year, you can avoid catastrophe with at least one working​ drive?

This is P(X \ geq 1) when n = 4

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744

99.999744% probability that during a​ year, you can avoid catastrophe with at least one working​ drive

7 0
3 years ago
If the area of Bianca’s rectangular backyard patio is represented by the expression x2−18x + 81, and the length of the patio is
frosja888 [35]

Answer:

a square backyard with width (x - 9)

Step-by-step explanation:

x²−18x + 81 = x² - (2 x 9) x + 9² = (x - 9)²

width = area / length = (x - 9)² / (x - 9) = x - 9

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Step-by-step explanation:

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Answer: B

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Step-by-step explanation:

Given that:

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Collecting the like term by rearranging the expression

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The like terms in the expression above are

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The correct option is B:

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4 0
3 years ago
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BaLLatris [955]

Answer:

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Step-by-step explanation:

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Using side a as the base, 6 points makes 5 bases.  With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments.  This equals 15 bases.  Each of these can connect to a point on line b.  15x4=60

36+60=96

5 0
3 years ago
Read 2 more answers
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