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The answer is c, hope this helps
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Answer:
The Hardy Weinberg equation is defined as p squared plus two p Q plus Q Squared equals one, and this equation is used to determine if evolution is occurring in a particular population. So P is defined as the dominant Ulliel frequency and cue is defined as the recess of illegal frequency. So if one of these illegal frequencies is given, we can easily find the frequency value for the other a wheel. So let's say that the dominant frequency, the dominant Ulliel here, is defined as a one. We have another legal called a two, so let's say a one is given. So to find a to all we need to dio so a two frequency would be equal toe one minus a one. And once we have the value of A to we can determine the hetero zegas frequency by solving this part of the equation. So we would just do two times a one times a two, and that would give us the frequency of the hetero Zika's individuals. Okay,