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Marat540 [252]
3 years ago
9

2x + 2 > 10. A. X<4 B. X>4 C. X<6 D. X>6

Mathematics
2 answers:
OLga [1]3 years ago
8 0
2x + 2 > 10
2x + 2 - 2 > 10 - 2
2x > 8
2x / 2 > 8 / 2
X > 4
snow_tiger [21]3 years ago
6 0
The answer would be A im pretty sure
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Rewrite 81 as 3 to some power.
NikAS [45]
First, let's find all the factors of 81:

81/3=27
27/3=9
9/3=3
3/1=1

So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).

This means we can write down 81 as 3*3*3*3 or 3^{4} - which is the answer to the question! (three to the power of 4)
5 0
3 years ago
Given the function h(x) = x2 – 7x + 6, determine the average rate of change of
guapka [62]

Step-by-step explanation:

the average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.

so,

(h(7) - (h(3)) / (7 - 3)

h(7) = 7² - 7×7 + 6 = 49 - 49 + 6 = 6

h(3) = 3² - 7×3 + 6 = 9 - 21 + 6 = -6

7 - 3 = 4

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the average change rate in that interval is 3 (or fully 3/1).

4 0
3 years ago
Elena and Jorge have similar problems and find the same answer. Each determines that the solution to e problem is 24.
Colt1911 [192]

What is the question??

6 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
Type the missing number to complete the porportion
Nataliya [291]
34 x 2 = 17 x 4

answer = 4
6 0
3 years ago
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