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grin007 [14]
3 years ago
15

Please help. urgent. needs explanation too :( thank you

Chemistry
1 answer:
g100num [7]3 years ago
3 0

Answer:

24) F. 3 mol.......ratio of hydrogen and oxygen is 2:1 , if hydrogen 6 then oxygen 3

25) B. 2.5 moles ......take ration fo 2RbNO3 and O2 which is 2:1 then if RbNO3 has 5 moles these O2 will have 2.5 moles

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Answer:chemical markers

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What is the group number of the most metallic group that contains metalloids?
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How many liters of 
Kruka [31]
The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.  
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol  = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions, 
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol  x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
3 0
4 years ago
How many molecules of F2 react with 66.6 g NH3 ? (stoichiometry)
stiks02 [169]
<h3>Answer:</h3>

5.89 × 10^23 molecules of F₂

<h3>Explanation:</h3>

The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;

5F₂ + 2NH₃ → N₂F₄ + 6 HF

We are given 66.6 g NH₃

We are required to determine the number of fluorine molecules

<h3>Step 1: Moles of Ammonia </h3>

Moles = Mass ÷ Molar mass

Molar mass of ammonia = 17.031 g/mol

Moles of NH₃ = 66.6 g ÷ 17.031 g/mol

                      = 3.911 moles

<h3>Step 2: Moles of Fluorine </h3>

From the equation 5 moles of Fluorine reacts with 2 moles of ammonia

Therefore,

Moles of fluorine = Moles of Ammonia × 5/2

                            = 3.911 moles × 5/2

                           = 9.778 moles

<h3>Step 3: Number of molecules of fluorine </h3>

We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules

Therefore;

1 mole of F₂ = 6.022 × 10^23 molecules

Thus,

9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole

                              = 5.89 × 10^23 molecules

Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules

5 0
3 years ago
Gaseous ammonia chemically reacts with oxygen gas to produce nitrogen monoxide gas and water vapor. Calculate the moles of oxyge
AlekseyPX

Answer: The correct answer will be 5 moles, because according to the  stoichiometric ratio, 5 moles of oxygen produce 6 moles of water.

Explanation:

The balanced equation is:

4NH_{3} + 5O_{2} ⇒ 4NO + 6H_{2}O

As you can see in the balanced reaction, it is necessary 5 moles of oxygen for obtain 6 moles of water. This stoichiometric ratio can be used for calculate any amount of produced water, once you have a specific amount of oxygen.

8 0
4 years ago
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