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sergeinik [125]
3 years ago
8

What is the atomic number of carbon?

Chemistry
1 answer:
7nadin3 [17]3 years ago
5 0

Atomic number of an element is the number of protons present in that element. It is unique for each element. The atomic number of carbon is 6.

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Which example of variation within species (select all correct answers)
s344n2d4d5 [400]
3 and 4 because the other two answers are different species.
6 0
3 years ago
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What reaction might we use to synthesize nickel sulfate, NiSO4?
guapka [62]

As I understand from your question, we should synthesize nickel sulfate first from nickel (II) oxide and sulfuric acid and second from nickel carbonate and sulfuric acid.

The chemical reactions will look like this:

NiO (s) + H₂SO₄ (aq) → NiSO₄ (aq) + H₂O (l)

NiCO₃ (aq)* + H₂SO₄ → NiSO₄ (aq) + H₂CO₃ (aq)

but carbonic acid will decompose to carbon dioxide and water

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8 0
3 years ago
An atom of sodium-23 (Na-23) has a net charge of
maksim [4K]

Answer:

Protons= 11

neutrons= 12

electrons = 10

Explanantion:

Look for Na on periodic table

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Atomic Mass = 23 (round it to be an integer)

Number of protons = Atomic number = 11

Number of neutrons = Atomic mass - atomic number = 23-11 =12

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6 0
3 years ago
25.0 mL of nitrous acid (HNO2) is titrated with a 1.235 M solution of KOH. The equivalence point (stoichiometric point) is obser
tatuchka [14]

Answer:

0.456 M

Explanation:

Step 1: Write the balanced neutralization equation

HNO₂ + KOH ⇒ KNO₂ + H₂O

Step 2: Calculate the reacting moles of KOH

9.26 mL of 1.235 M KOH react.

0.00926 L × 1.235 mol/L = 0.0114 mol

Step 3: Calculate the reacting moles of HNO₂

The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.

Step 4: Calculate the initial concentration of HNO₂

0.0114 moles of HNO₂ are in 25.0 mL of solution.

[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M

3 0
3 years ago
A non-metallic atom(at.no. 9) forms a molecule of the same,containing a single covalent bond. give reason
bezimeni [28]
They are so may forms
4 0
3 years ago
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