My thought would be B) gases.
I could be wrong but that's what i'd say
The equilibrium constant k is actually the ratio of the
concentration of the products over the concentration of reactants at equilibrium. So if the
concentration of products < concentration of reactants, therefore the
constant k will be small. But if the concentration of products >
concentration of reactants, the constant k will be large. In this case the
value is too small (x10^-19), therefore we can say that the reaction favors the
reactant side:
the equilibrium lies far to the left
n = PV/RT
p = 1.6 atm
v = 12.7L
R = 0.0821
T = 24°C which is equivalent to 297.15 degrees k
n = (16 × 12.7) / (0.0821 × 297.15)
n = 20.32 / 24.39
n = 0.83 mol
C = 12.90
H = 1.0079
C2 = 12.010 × 2 = 24.02
H6 = 1.0079 × 6 = 6.0474
C2H6 = 30.0674
Ethane times n which is 30.0674 × 0.83mol
= 24.95 grams of C2H6. Which is Ethane.
Oxidation is the loss of electrons and corresponds to an increase in oxidation state. Reduction is the gain of electrons and corresponds to a decrease in oxidation state. Balancing redox reactions can be more complicated than balancing other types of reactions because both the mass and charge must be balanced. Redox reactions occurring in aqueous solutions can be balanced by using a special procedure called the half-reaction method of balancing. In this procedure the overall equation is broken down into two half-reactions: one for oxidation and the other for reduction. The half-reactions are balanced individually and then added together so that the number of electrons generated in the oxidation half reaction is the same as the number of electrons consumed in the reduction half-reaction.
Answer:
TRUE
Explanation: because it is positively charged and protons are positive ions
